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Diborane (B2H6) is a propellant. combustion reaction of diborane is as follows: B2H6(s) + 302(g) – B2O3(s) + 3H2O (g) AHO= -2032.9 kJ Calculate the AH° (in kJ) for the combustion of 198 g of B2H6. Enter values with two decimal places. Include negative sign if the answer is negative. Molar masses: B2H6 = 27.66 g/mol, 02 = 32 g/mol, B203 = 69.62 g/mol, H20 = 18.02 g/mol

Diborane (B2H6) is a propellant. combustion reaction of diborane is as follows: B2H6(s) + 302(g) – B2O3(s) + 3H2O (g) AHO= -2032.9 kJ Calculate the AH° (in kJ) for the combustion of 198 g of B2H6. Enter values with two decimal places. Include negative sign if the answer is negative. Molar masses: B2H6 = 27.66 g/mol, 02 = 32 g/mol, B203 = 69.62 g/mol, H20 = 18.02 g/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Diborane (B2H6) is a propellant. The combustion reaction of diborane is as follows: B2H6(s) + 302(g) - B203(s) + 3H2O (g) AHO= -2032.9 kJ Calculate the AHO (in kJ) for the combustion of 198 g of B2H6. Enter values with two decimal places. Include negative sign if the answer is negative. Molar masses: B2H6 = 27.66 g/mol, 02 = 32 g/mol, B203 = 69.62 g/mol, H20 = 18.02 g/mol %3D
Transcribed Image Text:Diborane (B2H6) is a propellant. The combustion reaction of diborane is as follows: B2H6(s) + 302(g) - B203(s) + 3H2O (g) AHO= -2032.9 kJ Calculate the AHO (in kJ) for the combustion of 198 g of B2H6. Enter values with two decimal places. Include negative sign if the answer is negative. Molar masses: B2H6 = 27.66 g/mol, 02 = 32 g/mol, B203 = 69.62 g/mol, H20 = 18.02 g/mol %3D
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