Diagonalize the following matrix: 1 7 - 1 13 5 -5 -7 - 1 7 not diagonalizable 6 0 0 -9 0 0 - 12 90 0 06 0 00 - 12 9 0 0 6 0 0 0 - 0 = 0 0 - 12 = - 1 1 1 0 1 1 1 1 1 11 1 - 1 0 1 1 10 1 1 1 – 1 01 1 = 1 - - 1 L 13 5 1 7 -5 -1 -1 -7 7 1 13 5 7 -5 -7 1 - 1 7 1 13 7 5 -5 -7 1 1 7 1 1 1 0 1 -1 1 1 1 1 1 - 1 0 1 1 - 1 1 0 1 - 1 1 0 - 1 - 1 1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Diagonalize the following matrix:
1
7
- 1
13 5
-5 -7
- 1
7
not diagonalizable
6 0
0
-9
0 0 - 12
90 0
06 0
00 - 12
9 0
0 6
0
0
0
-
0
=
0
0
- 12
=
- 1 1
1
0 1 1
1 1 1
11 1
- 1 0 1
1 10
1 1
1
– 1
01 1
= 1
-
-
1
L
13 5
1
7 -5
-1 -1
-7
7
1
13 5
7 -5 -7
1 - 1
7
1 13
7
5
-5 -7
1 1 7
1 1 1
0 1 -1
1 1 1
1 1
- 1 0
1 1
-
1
1
0 1
-
1
1
0
- 1
- 1
1
Transcribed Image Text:Diagonalize the following matrix: 1 7 - 1 13 5 -5 -7 - 1 7 not diagonalizable 6 0 0 -9 0 0 - 12 90 0 06 0 00 - 12 9 0 0 6 0 0 0 - 0 = 0 0 - 12 = - 1 1 1 0 1 1 1 1 1 11 1 - 1 0 1 1 10 1 1 1 – 1 01 1 = 1 - - 1 L 13 5 1 7 -5 -1 -1 -7 7 1 13 5 7 -5 -7 1 - 1 7 1 13 7 5 -5 -7 1 1 7 1 1 1 0 1 -1 1 1 1 1 1 - 1 0 1 1 - 1 1 0 1 - 1 1 0 - 1 - 1 1
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