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ди = k ôt Solve the heat equation: 00, subject to boundary conditions: (0,t) = 0 and ôx (L,t) = 0 for t>0, with initial condition: u(x, 0) = – 2 sin(tx/L).

ди = k ôt Solve the heat equation: 00, subject to boundary conditions: (0,t) = 0 and ôx (L,t) = 0 for t>0, with initial condition: u(x, 0) = – 2 sin(tx/L).

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Solve the heat equation: 0 <x<L, t>0, subject to boundary conditions: ôt ôu (0,t) = 0 and ôx (L,t)= 0 for t>0, with initial condition: u(x, 0) = – 2 sin(tx/L).
Transcribed Image Text:Solve the heat equation: 0 <x<L, t>0, subject to boundary conditions: ôt ôu (0,t) = 0 and ôx (L,t)= 0 for t>0, with initial condition: u(x, 0) = – 2 sin(tx/L).
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