QUESTION 9Using Hess's Law and the equations (1)-(3) below calculate AH° at 25°C for coal gasification:2 C(coal) + 2 H₂O(g) →→→ CH4(g) + CO2(g)1. CO(g) + H2(g) →C(coal) + H₂O(g)2. CO(g) + H₂O(g) →CO2(g) + H2(g)→ CH4(9) + H₂O(g)3. CO(g) + 3 H2(g)OA. +116 kJ/molOB. +15 kJ/molOC-116 kJ/molAH°=?OD.-372 kJ/molOE-378 kJ/molAH° = -131 kJ/molAH°=-41 kJ/molAH°=-206 kJ/molMacBook Airmit. Click Save All Answers to save all answers. Question Completion Status:QUESTION 10The apparatus shown consists of three bulbs, connected by stopcocks. Bulb A contains CO2 at a pressure of 2.35 atm and has a volume of 3.05 L. Bulb B is empty andhas a volume of 1.0 L. Bulb C contains Ar at a pressure of 3.57 atm and has a volume of 2.75 L. What is the total pressure inside the system after the stopcocks areopened and the gases freely mix? Assume the lines connecting the bulbs have zero volume and the temperature remains constant. Enter the answer to 3 significantfigures.ACIncBook Air8JF104F11

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ΔΗ° = ? QUESTION 9 Using Hess's Law and the equations (1)-(3) below calculate AH at 25°C for coal gasification: 2 C(coal) + 2 H₂O(g) →→→ CH4(g) + CO2(g) 1. CO(g) + H₂(g) →C(coal) + H₂O(g) CO(g) + H₂O(g) → CO2(g) + H2(g) CH4(g) + H2O(g) AH°=-131 kJ/mol AH°=-41 kJ/mol AH°=-206 kJ/mol

ΔΗ° = ? QUESTION 9 Using Hess's Law and the equations (1)-(3) below calculate AH at 25°C for coal gasification: 2 C(coal) + 2 H₂O(g) →→→ CH4(g) + CO2(g) 1. CO(g) + H₂(g) →C(coal) + H₂O(g) CO(g) + H₂O(g) → CO2(g) + H2(g) CH4(g) + H2O(g) AH°=-131 kJ/mol AH°=-41 kJ/mol AH°=-206 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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