Calculate the enthalpy of the reaction 4B(s) + 302(9)→2B2O3 (s) given the following pertinent information: А. В-О3(:) + зНа0(9) -+30;(9) + В,Но (9), Д,Н; —+2035 kJ mol 1 B. 2B(s) + 3H2(9)¬→B2H6(g), c. H2 (9) + O2(9)→H2O(1), D. H2O(1)→H2O(g), A,H÷ = +36 kJ mol-1 A,HƐ = -285 kJ mol +44 kJ mol- Express your answer with the appropriate units.

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Chapter1: Chemical Foundations
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Part B
Calculate the enthalpy of the reaction
4B(s) +302(9)→2B2O3(s)
given the following pertinent information:
A. B2O3 (s) + 3H20(g)→302(g)+B,H6(9), A,H = +2035 kJ mol-1
B. 2B(s) + 3H2(g)→B2H6(9),
c. H2(9) + ¿O2(9)→H½O(1),
D. H2O(1)→H20(g),
A,H = +36 kJ mol-1
A,HƐ = -285 kJ mol 1
A,Hß = +44 kJ mol¬
Express your answer with the appropriate units.
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HA
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A;H° =
Value
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Transcribed Image Text:Part B Calculate the enthalpy of the reaction 4B(s) +302(9)→2B2O3(s) given the following pertinent information: A. B2O3 (s) + 3H20(g)→302(g)+B,H6(9), A,H = +2035 kJ mol-1 B. 2B(s) + 3H2(g)→B2H6(9), c. H2(9) + ¿O2(9)→H½O(1), D. H2O(1)→H20(g), A,H = +36 kJ mol-1 A,HƐ = -285 kJ mol 1 A,Hß = +44 kJ mol¬ Express your answer with the appropriate units. • View Available Hint(s) HA ? A;H° = Value Units
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