Devise a synthesis to prepare 2,7-dimethyldec-5-yn-3-ol from 1,2-epoxy-3-methylbutane and 3-methyl-1-hexene. Part 1: Draw the structure for compound A. Part 2: Identify the required reagents for step 1. Select the single best answer. Part 3: Identify the required reagents for step 2. Select the single best answer. **Title:** Synthesis of 2,7-Dimethyldec-5-yn-3-ol**Objective:** Devise a synthesis to prepare 2,7-dimethyldec-5-yn-3-ol from 1,2-epoxy-3-methylbutane and 3-methyl-1-hexene.---**Reaction Scheme:**1. **Starting Materials:** - 1,2-Epoxy-3-methylbutane - 3-Methyl-1-hexene2. **Reaction Sequence:** - **Initial Step:** - Combine 3-methyl-1-hexene with chlorine (Cl2). - Product 'A' is formed. - **Step 1:** - React product 'A' with 1,2-epoxy-3-methylbutane. - Intermediate product is formed with an alkyne group positioned in the middle of the chain. - **Step 2:** - Final transformation to the target molecule: 2,7-dimethyldec-5-yn-3-ol, featuring a hydroxyl (OH) group on the tertiary carbon adjacent to the alkyne.**Diagram Key:**- The reaction involves epoxide opening and alkyne formation.- The structures show alkyne, epoxide, and alcohol functional groups emphasizing the synthetic strategy.**Conclusion:**The resulting molecule, 2,7-dimethyldec-5-yn-3-ol, is synthesized through strategic use of addition, elimination, and functional group transformation reactions. This showcases the integration of knowledge on epoxides and alkynes in organic synthesis. ### Chemistry Problem Set#### Part 1 of 3**Task:** Draw the structure for compound A.- **Instructions:** Click and drag to start drawing a structure. [Interactive Drawing Box]---#### Part 2 of 3**Task:** Identify the required reagent(s) for step 1. Select the single best answer.- **Options:** - NaN₃ - NaNH₂ (1 eq.) - Na, NH₃ - NaNH₂ (2 eq.) - KOC(CH₃)₃---#### Part 3 of 3**Task:** Identify the required reagent(s) for step 2. Select the single best answer.- **Options:** - NaNH₂ - H₂SO₄ - 1. NaOH; 2. H₂O - Na, NH₃ - 1. NaNH₂; 2. H₂O---Use the interface to select your answers and submit your responses. Each question is designed to test your understanding of chemical reactions and reagent selection.

Organic synthesis involves the reaction of an organic compound with a reagent or another organic molecule to form a new molecule. A reagent is a molecule, which is of organic or inorganic nature. It helps in the conversion of functional groups, removal of leaving groups, addition or substitution of new groups. Here, we have been given a reaction scheme. We have to find the missing reagents and products formed in this reaction. The given reaction scheme is the synthesis of 2,7-dimethyldec-5-yn-3-ol from 1,2-epoxy-3-methylbutane and 3-methyl-1-hexene. It is given that the reaction takes place in two steps. In the first step, the product obtained after reaction between 3-methyl-1-hexene and chlorine is treated with a reagent to form 3-methyl-1-hexyne. The reaction of an alkene with chlorine yields a dichloro alkane. The dichloroalkane when treated with NaNH2 we will get an alkyne. In the second step, the 3-methyl-1-hexyne is reacted with 1,2-epoxy-3-methylbutane. The proton of an alkyne is acidic and can be abstracted by a strong base. Thus, in presence of a strong base in aqueous medium, we get the final product. The reaction of an alkene with a chlorine molecule results in the formation of a dichlorocompound. The chlorination results in the formation of a vicinal dihalide. In step 1, a vicinal dihalide is converted to an alkyne. For this reaction, we use NaNH2. The reaction is shown below. NH2- or amide ion is a strong base and abstracts a proton from the adjacent C atom. This causes the Cl- to leave and form an alkene. Another proton is then abstracted and, the other Cl- also leaves to form the alkyne. Thus, 2 equivalents of NaNH2 is required for this reaction. NaN3: it converst an alkyl halide to azide not to alkyne. Hence, it is not used. NaNH2(1 eq): For the reaction, we require two equivalents. Hence, it is incorrect. Na/NH3: It converts an alkyne to alkene. We require a reagent that converts a vicinal halide to alkyne. Hence, it is not used. KOC(CH3)3: It is a strong base, but it is not strong compared to NaNH2. So, it is not used. The step 2 involves the reaction between the alkyne and the epoxide ring. We need to open the epoxide ring. We require a nucleophile to open the ring. We can convert the alkyne to a nucleophile by treating it with a strong base. So, NaNH2 can be used. The nucleophilic opening of epoxide results in the formation of alkoxide ion, alkoxide ion can be converted to alcohol by hydrolysis. The base abstracts proton and forms the nucleophile. The nucleophile attacks epoxide ring and forms the oxide ion. The oxide ion abstracts a proton from water and forms the final product. The reagents are: 1. NaNH2 2. H2O. NaNH2: We need a water molecule too. Hence, it is incorrect. H2SO4: It can help in the ring opening but we need a reagent for the conversion of alkyne to nucleophile. But no such reagent is present in this option, hence incorrect. 1. NaOH, 2. H2O: NaOH is a strong base, but it is not strong compared to NaNH2. So, it is not used. Na/NH3: It converts an alkyne to alkene. We require a base to convert an alkyne to nucleophile. Hence, it is not used. Part 1: Structure of compound A:Part 2: Reagent for step 1 is NaNH2(2 eq)Part 3: Reagents for step 2 are 1. NaNH2 2. H2O.