Devise a detailed mechanism for formation of the major product of the elimination reaction below. CH3 H2SO4 -CHH Draw curved arrows to show electron reorganization for the mechanism step below. Make the ends of your arrows specify the origin and destination of reorganizing electrons. Arrow-pushing Instructions H. H. :0-H CH3 H
Devise a detailed mechanism for formation of the major product of the elimination reaction below. CH3 H2SO4 -CHH Draw curved arrows to show electron reorganization for the mechanism step below. Make the ends of your arrows specify the origin and destination of reorganizing electrons. Arrow-pushing Instructions H. H. :0-H CH3 H
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Detailed Mechanism for Elimination Reaction**
In this exercise, we will devise a mechanism for the formation of the major product in the elimination reaction depicted below.
**Reaction Overview:**
The reaction involves the starting material, a cyclic alcohol with a methyl group, reacting with sulfuric acid (\( \text{H}_2\text{SO}_4 \)) to undergo dehydration, forming an alkene.
**Mechanism Step:**
1. **Protonation Step:**
- The hydroxyl group (\(-OH\)) on the cyclic structure is protonated by sulfuric acid, resulting in water (\( \text{H}_2\text{O} \)) being a good leaving group.
**Arrow-Pushing Instructions:**
To understand the electron reorganization, curved arrows should be used. The arrows indicate the movement of electrons.
**Diagram Explanation:**
- The first carbon structure represents the cyclic alcohol with a methyl group and an adjacent hydrogen.
- Upon interaction with the acid, a positive charge is indicated on the carbon atom where the water will leave.
- The lone pairs of electrons on the oxygen of the incoming water molecule are shown.
The ultimate goal is to demonstrate the formation of a carbocation intermediate, where an elimination of the water molecule occurs, leading to the formation of a double bond and resulting in an alkene as the product.
Remember to use the correct direction for arrow pushing; typically, arrows start from electron-rich areas (like lone pairs or negative charges) and move towards electron-deficient areas (like positive charges).
**Instruction Note:**
Ensure the placement of arrows correctly follows electron flow conventions for a clear understanding of the mechanistic steps.
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