Determire the reactiors of the given beam using morment distribution method. w = 25 kN/m, P: = 25 kN, ard P2 = 25 kN P₁ P2 RA RB- Numerical answer in 4 decimal places and positive values only: khN (Dowrwvard) MB Rc W 8 m m 21 kN-m KN (Upward) V kN (Upward) B 2m 2m 2m
Determire the reactiors of the given beam using morment distribution method. w = 25 kN/m, P: = 25 kN, ard P2 = 25 kN P₁ P2 RA RB- Numerical answer in 4 decimal places and positive values only: khN (Dowrwvard) MB Rc W 8 m m 21 kN-m KN (Upward) V kN (Upward) B 2m 2m 2m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please answer in complete solution and draw an fbd.
Note: Please use the second picture as guide for the formulas. Thanks°
Transcribed Image Text:Determine the reactions of the given beam using moment distribution method. w = 25 kN/m, P₁ = 25 kN, and P₂ = 25 KN
P₁
P2
1.1
V 2m
RA=
Numerical answer in 4 decimal places and positive values only:
RB =
MB =
Rc =
W
8 m
21
kN (Downward)
kN-m
KN (Upward)
kN (Upward)
B
2m
2m
C
Transcribed Image Text:Sign convention - consider clockwise rotation is positive, counterclockwise is negative.
MBA
MAR
Fixed End Moments (FEM) - moment at the wall or fixed joint
MBA
MAB
Stiffness Factor - required moment M to rotate the end A of the beam 0 = 1 rad.
4EI
(absolute) K =
far end fixed
3EI
K=far end hinged
M
1
M' = M, far end fixed
(relative) K ==, E is constant
L'
3EI
M
(relative) K =
Carry-Over Moment - the moment induced at the fixed end of a beam by the action of the moment
applied at the other end.
4L
-, far end hinged
B
M' = 0, far end hinged
Distribution Factor, DF - the distribution factor at a joint of a member is the ratio of the bending
stiffness of the member to the sum of bending stiffness of all the members connected to the joint.
к
DF=;
ΣΚ
Note: DF = 1, for hinge or roller support
DF = 0, for fixed support
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