Determine  Y component of reaction at A Y component of reaction at B X component of reaction at E  moment of reaction at E  Y component of reaction at E

Abar AB is attached at A as fixed support. A small spaces can be seen on the other side of the bar prior to another rigid surface. Load P is applied on the bar located at two-thirds of length L from point A. Determine the small space s if the support reactions at A and B are to be equal due to the external load P. See all necessary parameters below. A L 2.5 m A 1800 mm² E 50 GPa 90 KN EP 2 =L 3 1 mm 3 mm L ANSWERS: ALL ANSWERS SHOULD BE IN THREE (3) DECIMAL PLACES INCLUDING ZEROS 81 (delta due to external load P) = 82 (delta due to Reaction at B) = Small Space s = mm ,S₁ B

The frame shown below is subjected to an applied Point Load of 27kN and a Uniformly Distributed Load of 3kN/m and is supported at A by a pinned connection and at B by a roller connection. Calculate the vertical support reaction at B. Give your answer in kN to 2dp. 3m 3m PL UDL 5m A

If the load P on the beam below causes the end C to be displaced 10mm downward, determine 4. the normal strain in wires CE and BD. 4 m A B 3 m- -2m

A bar AB is attached at A as fixed support. A small spaces can be seen on the other side of the bar prior to another rigid surface. Load P is applied on the bar located at two-thirds of length L from point A. Determine the small space s if the support reactions at A and B are to be equal due to the external load P. See all necessary parameters below. L A E P A 3 m 2500 mm² GPa 45 77 KN 2/3 -L 113 mm -L ANSWERS: ALL ANSWERS SHOULD BE IN THREE (3) DECIMAL PLACES INCLUDING ZEROS 01 (delta due to external load P) = 52 (delta due to Reaction at B) = Small Space s = mm S₁ mm B

Frame ABCDE shown in Figure Q2 is supported by a fixed connection at B, roller at D and pinned at A. The frame carries 200 kN horizontal point load acting at the middle of member AC, 50 kN point load at point E and 50 kN/m uniform distributed load on member BC. El is constant. (a) (b) 2 m 2 m 50 kN/m 200 kN 6 m Figure Q2: Frame [Rajah Q2: Kerangka] 6 m 1041 Next, calculate the fixed-end moment (FEM) for all members. 50 KN 2m E For the case of no sway, calculate the value of stiffness (K) and distribution factor (DF) for each member.

Given: Consider the truss shown below and the series of loading. 20 k Required: 8⁹ An 8⁹ 8⁹ 8' 8' a 10 k 8' (A) (A) Calculate the force in member bd for case (A) (B) Calculate the force in member bd for case (B) (C) Calculate the force in member bd using the principle of superposition for the truss loading below. DO NOT use equilibrium equations. 10 k d 5 k a 8⁹ 8' (B) b 8'

Both sections are made of steel with E-200 GPa. The gap between the bottom of the metal bar and the floor is 4.5 mm. The top section is 300mm long and its area is 250 mm² with a force of 300 kN acting at its center and the bottom section is 300 mm and its area is 400 mm² with a force of 600 kN acting at its center. Calculate Rc and RA. ↓ C B

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Assuming that E=200 GPa and I=2.63x108 mm4, determine the total force P exerted by the 25 mm diameter, 2m long steel rod at B.