Determine which type of hypothesis test is appropriate (if any) in each situation.  Type 1: test a population mean, population standard deviation is known Type 2: test a population mean, population standard deviation is unknown Type 3: test  a population proportion Then Clearly state the null and alternative hypothesis. Then, compute the test statistic, and determine the conclusion of the test. (You may compute a p-value or use critical values to determine the conclusion of the test) The director of research and development is testing a new medicine. She wants to know if there is evidence at the 0.05 level that the medicine relieves pain in more than 320 seconds. For a sample of 32 patients, the mean time in which the medicine relieved pain was 325 seconds. Assume the population standard deviation is 23. Make the decision to reject or fail to reject the null hypothesis

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Determine which type of hypothesis test is appropriate (if any) in each situation.  Type 1: test a population mean, population standard deviation is known Type 2: test a population mean, population standard deviation is unknown Type 3: test  a population proportion Then Clearly state the null and alternative hypothesis. Then, compute the test statistic, and determine the conclusion of the test. (You may compute a p-value or use critical values to determine the conclusion of the test) The director of research and development is testing a new medicine. She wants to know if there is evidence at the 0.05 level that the medicine relieves pain in more than 320 seconds. For a sample of 32 patients, the mean time in which the medicine relieved pain was 325 seconds. Assume the population standard deviation is 23. Make the decision to reject or fail to reject the null hypothesis
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Given Hypotheses

The Population mean : μ = 320 secondsandPopulation Standard Deviation : σ = 23 secondsFrom the sample,Sample size: n = 32Sample mean: x¯ = 325 seconds

 

To test :H0 : μ = 320 seconds    vs     H1 : μ > 320 seconds

Test Statistic

The test statistic is obtained as:

 

z0 = x¯ - μσn   = 1.23 

 

The critical value is obtained as:

 

z0.05 = 1.645

 

As z0 = 1.23 < z0.05 = 1.645 we cannot reject H0 at 5% level of significance 

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