Determine whether the given procedure results in a binomial distribution. If not, state the reason why.
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Determine whether the given procedure results in a bionomal distribution.
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- Measurements for the length and width of a rectangular plastic covers for CDs are rounded to the nearest mm (so they are discrete). Let X denote the length and Y denote the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16 mm. The joint distribution is given by the following table: X=length 129 130 131 Y=width 15 0.12 0.42 0.06 16 0.08 0.28 0.04 The probability that a CD cover has width of 16 mm knowing that it has a length of 129 mm is: 0.4 0.2 0.13 0.08According to the Carnegie unit system, the recommended number of hours students should study per unit is 2. Are statistics students' study hours more than the recommended number of hours per unit? The data show the results of a survey of 11 statistics students who were asked how many hours per unit they studied. Assume a normal distribution for the population. 2, 2.9, 4.5, 0.7, 3.3, 4.5, 4.2, 1.2, 0.9, 1.8, 2.8 What can be concluded at the αα = 0.05 level of significance? The p-value = (Please show your answer to 4 decimal places. Based on this, we should Select an answer fail to reject accept reject the null hypothesis Thus, the final conclusion is that ... The data suggest the populaton mean is significantly more than 2 at αα = 0.05, so there is enough evidence to conclude that the population mean study time per unit for statistics students is more than 2. The data suggest the population mean is not significantly more than 2 at αα = 0.05, so there is enough evidence to…Measurements for the length and width of a rectangular plastic covers for CDs are rounded to the nearest mm (so they are discrete). Let Xx denote the length and Y denote the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16 mm. The joint distribution is given by the following table: X=length 129 130 131 Y=width 15 0.12 0.42 0.06 16 0.08 0.28 0.04 The probability that a CD cover has width of 16 mm knowing that it has a length of 131 mm is:
- The table below shows the distribution of the sizes of a random sample of 290 households that were included in a survey conducted at Nyamebekyere about a month ago.Household Size Number of Households142 113 244 385 456 557 468 309 2110 1011 4 12 2 Total 290a) Use the data to draw a histogram and describe the shape of the distribution.b) Calculate the:i. Modeii. Medianiii. Meaniv. Rangev. Variancevi. Standard Deviationc) The mean household size of Nyamebekyere, which was 7.1 about 10 years ago, is suspected to have changed. Conduct a significance test to ascertain whether this suspicion is backed by empirical evidence using an alpha level of 3%. [Hint: In computing your test statistic, use the sample mean and sample standard deviation you have already calculatedDetermine the minimum sample size required when you want to be 95% confident that the sample mean is within two units of the population mean and = 4.3. Assume the population is normally distributed. n =Calculate the 1. Population and sample skewness, add interpretation 2. Exact and excess sample kurtosis, add interpretation
- 7. Assume the following normal distribution to represent the plasma cholesterol values of randomly selected individuals in mmol/L. o = 0.5 5.2 a. Convert 4.15 mmol/L to z score. b. Convert 6.55 mmol/L to z score. c. Convert 4.39 mmol/L to z score. d. What value in mmol/L corresponds to a z score of 1.38? e. What value in mmol/L corresponds to a z score of -0.44? f. Find P(X s 5.89) g. Find P(X 2 4.59) h. Find P(4.39 sX< 5.60) i. Find x such that P(X 2 x) = 0.0359 j. Find x such that P(4.98 s Xs x) = 0.6598According to the Carnegie unit system, the recommended number of hours students should study per unit is 2. Are statistics students' study hours different from the recommended number of hours per unit? The data show the results of a survey of 16 statistics students who were asked how many hours per unit they studied. Assume a normal distribution for the population. 1.5, 2, 2.9, 3.8, 4.6, 1.1, 1.8, 2.6, 1.4, 2.8, 4.5, 1.2, 1, 0.7, 3, 1.2 What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer < ≠ = > H1:H1: ? p μ Select an answer < ≠ = > The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to…According to the Carnegie unit system, the recommended number of hours students should study per unit is 2. Are statistics students' study hours more than the recommended number of hours per unit? The data show the results of a survey of 12 statistics students who were asked how many hours per unit they studied. Assume a normal distribution for the population. 1.2, 4.3, 4.5, 1.4, 1.5, 2.7, 1.8, 2.4, 1.3, 2, 2.2, 1.3 What can be concluded at the αα = 0.05 level of significance? A. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly more than 2 at αα = 0.05, so there is enough evidence to conclude that the population mean study time per unit for statistics students is more than 2. The data suggest the population mean is not significantly more than 2 at αα = 0.05, so there is enough evidence to conclude that the population mean study time per unit for statistics students is equal to 2. The data suggest that the population mean study time per…
- a. State incidence of Chlamydla (per 1,000 population) b. Case fatality rate of syphilis C. Cause-specific death rate of AIDS (per 10,000 population)The contents (in ml) of a sample of 18 bottles of locally distributed premium essential oils are given. 0.68, 1.29, 0.93, 1.02, 0.74, 1.43, 1.29, 1.20, 0.68, 1.46, 1.33, 1.14, 1.33, 1.46, 0.74 1.33, 1.02, 0.93. The midrange isA. 1.055B. 1.070C. 1.100D. 1.14