17.14 is the question i need answerd 17.7 is just the information that goes with it please use the calculator method to work out thank you ### Measuring Melting Point (continued)Here are six measurements (in °C) of the melting point of a copper sample:- 1084.55- 1084.89- 1085.02- 1084.79- 1084.69- 1084.86The copper sample is supposed to have a melting point of 1084.80°C. Do the measurements provide good evidence that the true melting point is not 1084.80°C?The six measurements are a Simple Random Sample (SRS) from the population of all results that we would obtain if we kept measuring the melting point of this copper sample indefinitely. This population follows a Normal distribution, with a mean equal to the true melting point of the copper sample and a standard deviation of 0.25. Use this information to carry out a test of significance, following the four-step process as illustrated in Example 17.7. **Example 17.7: Executives' Blood Pressures****State:**The National Center for Health Statistics reports that the systolic blood pressure for males age 50-59 years has a mean 130 and standard deviation 15. An insurance company looks at the medical records of 72 executives in this age group and finds that the mean systolic blood pressure in this sample is 128.07. Is this evidence that executives have a different mean systolic blood pressure from that of the general male population?**Plan:**To test whether the mean pressure differs from the national mean (μ₀ = 130), the hypotheses are:- H₀: μ = 130- Hₐ: μ ≠ 130A two-sided test is proper because the difference could be in either direction.**Solve:**The test statistic is calculated using the formula:\[ z = \frac{\bar{x} - \mu_0}{\sigma/\sqrt{n}} = \frac{128.07 - 130}{15/\sqrt{72}} = -1.09 \]To find the P-value, sketch the standard Normal curve and mark the observed value of \( z \).Figure 7.14 shows that the P-value is the probability that a standard Normal variable Z takes a value at least 1.09 away from zero. From Table A or software, \( P \) is:\[ P = 2P(Z > 1.09) = 2(0.1379) = 0.2758 \]**Conclude:**More than 27% of the time, an SRS of size 72 from the general male population would have a mean systolic blood pressure at least as far from 130 as that of the executives.The mean observed \( \bar{x} = 128.07 \) is therefore not good evidence that executives differ from other men.

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Description: 17.14 is the question i need answerd 17.7 is just the information that goes with it please use the calculator method to work out thank you ### Measuring Melting Point (continued)Here are six measurements (in °C) of the melting point of a copper sampl

step-1 Formulation of the null and alternative hypothesis. step-2 specified the level of…

Math

Statistics

EXAMPLE 17.7 Executives' B STATE: The National Center for Health Sta sure for males 50-59 years of age has m. medical director of a large company lookS in this age group and finds that the mean X = 128.07. Is this evidence that the com systolic blood pressure from the general pe PLAN: The null hypothesis is "no differenc alternative is two-sided because the medic tion in mind before examining the data. So u of the executive population are d :H We know that the one-sample z test is ap simple conditions. 44 VE: As part of the "simple conditions executives' systolic blood pressures follow tion o = 15. Software can now calculate a test statistic is Onl - X To help find the P-value, sketch the s observed value of z. Figure 17.4 shows standard Normal variable Z takes a value a or software, this probability is P 2P(Z> 1.09) %3D CONCLUDE: More than 27% of the time population would have a mean systolic blo of the executive sample. The observed x chat executives differ from other men.

EXAMPLE 17.7 Executives' B STATE: The National Center for Health Sta sure for males 50-59 years of age has m. medical director of a large company lookS in this age group and finds that the mean X = 128.07. Is this evidence that the com systolic blood pressure from the general pe PLAN: The null hypothesis is "no differenc alternative is two-sided because the medic tion in mind before examining the data. So u of the executive population are d :H We know that the one-sample z test is ap simple conditions. 44 VE: As part of the "simple conditions executives' systolic blood pressures follow tion o = 15. Software can now calculate a test statistic is Onl - X To help find the P-value, sketch the s observed value of z. Figure 17.4 shows standard Normal variable Z takes a value a or software, this probability is P 2P(Z> 1.09) %3D CONCLUDE: More than 27% of the time population would have a mean systolic blo of the executive sample. The observed x chat executives differ from other men.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN:9780547587776

Author:HOLT MCDOUGAL

Publisher:HOLT MCDOUGAL

Chapter1: Variables, Expressions, And Integers

Section1.5: Adding Integers

Problem 45E

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