17.14 is the question i need answerd 17.7 is just the information that goes with it please use the calculator method to work out thank you ### Measuring Melting Point (continued)Here are six measurements (in °C) of the melting point of a copper sample:- 1084.55- 1084.89- 1085.02- 1084.79- 1084.69- 1084.86The copper sample is supposed to have a melting point of 1084.80°C. Do the measurements provide good evidence that the true melting point is not 1084.80°C?The six measurements are a Simple Random Sample (SRS) from the population of all results that we would obtain if we kept measuring the melting point of this copper sample indefinitely. This population follows a Normal distribution, with a mean equal to the true melting point of the copper sample and a standard deviation of 0.25. Use this information to carry out a test of significance, following the four-step process as illustrated in Example 17.7. **Example 17.7: Executives' Blood Pressures****State:**The National Center for Health Statistics reports that the systolic blood pressure for males age 50-59 years has a mean 130 and standard deviation 15. An insurance company looks at the medical records of 72 executives in this age group and finds that the mean systolic blood pressure in this sample is 128.07. Is this evidence that executives have a different mean systolic blood pressure from that of the general male population?**Plan:**To test whether the mean pressure differs from the national mean (μ₀ = 130), the hypotheses are:- H₀: μ = 130- Hₐ: μ ≠ 130A two-sided test is proper because the difference could be in either direction.**Solve:**The test statistic is calculated using the formula:\[ z = \frac{\bar{x} - \mu_0}{\sigma/\sqrt{n}} = \frac{128.07 - 130}{15/\sqrt{72}} = -1.09 \]To find the P-value, sketch the standard Normal curve and mark the observed value of \( z \).Figure 7.14 shows that the P-value is the probability that a standard Normal variable Z takes a value at least 1.09 away from zero. From Table A or software, \( P \) is:\[ P = 2P(Z > 1.09) = 2(0.1379) = 0.2758 \]**Conclude:**More than 27% of the time, an SRS of size 72 from the general male population would have a mean systolic blood pressure at least as far from 130 as that of the executives.The mean observed \( \bar{x} = 128.07 \) is therefore not good evidence that executives differ from other men.

Name: 17.14 is the question i need answerd 17.7 is just the information that
Uploaded: 2024-03-20T07:06:27.000Z
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Description: 17.14 is the question i need answerd 17.7 is just the information that goes with it please use the calculator method to work out thank you ### Measuring Melting Point (continued)Here are six measurements (in °C) of the melting point of a copper sampl