Determine whether the given function is a solution to the given differential equation. ²0 de at² 0=5e²1-2e5t -0-20-23e5 dt The function 0-5e21-2e5t is not a solution to the differential equation d²0 at² de de -0+20= -23 e 5t, because when 5 e 21-2 e 5t is substituted for e, is substituted for and is substituted for dt dt d²e -, the two sides of the differential equation are not equivalent on any intervals of t a₁²
Determine whether the given function is a solution to the given differential equation. ²0 de at² 0=5e²1-2e5t -0-20-23e5 dt The function 0-5e21-2e5t is not a solution to the differential equation d²0 at² de de -0+20= -23 e 5t, because when 5 e 21-2 e 5t is substituted for e, is substituted for and is substituted for dt dt d²e -, the two sides of the differential equation are not equivalent on any intervals of t a₁²
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Determine whether the given function is a solution to the given differential equation.
d²e de
-0- -+20= -23 e 5t
dt² dt
0=5e²t_2e5t
The function 0 = 5 e 2t - 2 e 5t| is not a solution to the differential equation
d²0
dt²
←
de
- +20= -23 e 5t, because when 5 e 2t - 2 e 5t is substituted for 0.
dt
-0-
de
is substituted for and
dt
is substituted for
d²e
dt²
the two sides of the differential equation are not equivalent on any intervals of t.
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