Determine whether the following graph can represent a normal curve. ..... Could the graph represent a normal curve? Select all that apply. A. No, because the graph is always greater than or equal to zero. B. No, because the graph is not always greater than or equal to zero. OC. No, because the graph has a single peak. D. No, because the graph is symmetric about its mean. E. Yes, because the graph may not satisfy all of the criteria for a normal curve, but it satisfies at least one of the criteria. F. Yes, because the graph satisfies all of the criteria for a normal curve. G. No, because the highest point of the graph does not occur at the median. H. No, because the graph is not symmetric about its mean. No, because the graph has multiple peaks. J. No, because the highest point of the graph occurs at the mean. O Time Remaining:

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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Determine whether the following graph can represent a normal curve 

**Graph Description:**

The graph in question presents a wavy line that moves above and below the horizontal axis (x-axis). It features multiple peaks and troughs, indicating variability in its behavior.

**Determining Normal Curve Characteristics:**

The task is to evaluate whether the graph represents a normal curve. Here are the available choices:

- **A.** No, because the graph is always greater than or equal to zero.
- **B.** No, because the graph is not always greater than or equal to zero.
- **C.** No, because the graph has a single peak.
- **D.** No, because the graph is symmetric about its mean.
- **E.** Yes, because the graph may not satisfy all of the criteria for a normal curve, but it satisfies at least one of the criteria.
- **F.** Yes, because the graph satisfies all of the criteria for a normal curve.
- **G.** No, because the highest point of the graph does not occur at the median.
- **H.** No, because the graph is not symmetric about its mean.
- **I.** No, because the graph has multiple peaks.
- **J.** No, because the highest point of the graph occurs at the mean.

**Explanation:**
- A normal curve, or Gaussian distribution, typically has a single peak, is symmetric about the mean, and the highest point occurs at the mean. The depiction here shows a graph that has multiple peaks and lacks symmetry about the mean, which contradicts the features of a normal distribution.
- Therefore, the options that claim the graph cannot represent a normal curve (particularly due to multiple peaks and lack of symmetry) are more applicable.
Transcribed Image Text:**Graph Description:** The graph in question presents a wavy line that moves above and below the horizontal axis (x-axis). It features multiple peaks and troughs, indicating variability in its behavior. **Determining Normal Curve Characteristics:** The task is to evaluate whether the graph represents a normal curve. Here are the available choices: - **A.** No, because the graph is always greater than or equal to zero. - **B.** No, because the graph is not always greater than or equal to zero. - **C.** No, because the graph has a single peak. - **D.** No, because the graph is symmetric about its mean. - **E.** Yes, because the graph may not satisfy all of the criteria for a normal curve, but it satisfies at least one of the criteria. - **F.** Yes, because the graph satisfies all of the criteria for a normal curve. - **G.** No, because the highest point of the graph does not occur at the median. - **H.** No, because the graph is not symmetric about its mean. - **I.** No, because the graph has multiple peaks. - **J.** No, because the highest point of the graph occurs at the mean. **Explanation:** - A normal curve, or Gaussian distribution, typically has a single peak, is symmetric about the mean, and the highest point occurs at the mean. The depiction here shows a graph that has multiple peaks and lacks symmetry about the mean, which contradicts the features of a normal distribution. - Therefore, the options that claim the graph cannot represent a normal curve (particularly due to multiple peaks and lack of symmetry) are more applicable.
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