Determine the value of Ksp for SrF₂ by constructing an ICE table, writing the solubility constant expression, and solving the expression. Complete Parts 1-2 before submitting your answer. 2 NEXT > It is found that up to 0.0110 g of SrF₂ dissolves in 100 mL of aqueous solution at a certain temperature. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products at this temperature. Initial (M) Change (M) Equilibrium (M) 0 0.0110 8.76 x 10-5 -8.76 x 10-5 -8.76 x 10-4 -1.75 x 10-4 -1.75 x 10" [0] [8.76 x 10-412 SrF₂(s) 8.76 x 10-4 -8.76 x 10-4 0 [0.0110] [1.75 x 10-41² Ksp 14 [8.76 × 105] [1.75 x 10-² [8.76 x 104] [1.75 × 10-³² [0] Sr²+ (aq) [8.76 × 104] 2.68 x 10-⁹ 8.76 x 10-4 -8.76 x 10-4 8.76 x 10-4 1.75 x 10-4 Determine the value of Ksp for SrF₂ by constructing an ICE table, writing the solubility constant expression, and solving the expression. Complete Parts 1-2 before submitting your answer. < PREV 1 2 Using the values from the ICE table, construct the expression for the solubility constant. Each reaction participant must be represented by one tile. Do not combine terms Once the expression is constructed, solve for Ksp. [1.75 × 104] [1.53 × 106] + 2.68 x 10-⁹ 1.75 x 10" [1.75 × 10] [2.68 × 10-¹2] 2 F (aq) 1.75 x 10³ 1.75 x 107³ RESET -0.0110 [0.0110]² 7.18 x 10-18 RESET [8.76 x 10-51² [1.53 x 10-61²

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Determine the value of Ksp for SrF₂ by constructing an ICE table, writing the solubility
constant expression, and solving the expression. Complete Parts 1-2 before submitting
your answer.
NEXT >
It is found that up to 0.0110 g of SrF₂ dissolves in 100 mL of aqueous solution at a certain temperature. Fill
in the ICE table with the appropriate value for each involved species to determine concentrations of all
reactants and products at this temperature.
Initial (M)
Change (M)
Equilibrium (M)
0
0.0110
8.76 x 10-5
-8.76 x 10-5 -8.76 x 10-4 -1.75 x 10-4 -1.75 x 10™³
[0]
[8.76 x 10-¹1²
SrF₂(s)
8.76 x 10-4
-8.76 x 10-4
[0.0110]
0
Ksp
=
[8.76 x 104] [1.75 × 10-³²
[8.76 x 10-5]
[1.75 x 10-41² [1.75 x 10-¹²
Sr²+ (aq)
[0]
8.76 x 10-4
-8.76 x 10-4
8.76 x 10-4
[8.76 x 104]
2.68 x 10-⁹
Determine the value of Ksp for SrF₂ by constructing an ICE table, writing the solubility
constant expression, and solving the expression. Complete Parts 1-2 before submitting
your answer.
2
< PREV
1
2
Using the values from the ICE table, construct the expression for the solubility constant. Each reaction
participant must be represented by one tile. Do not combine terms Once the expression is constructed,
solve for Ksp.
1.75 x 10-4
[1.75 x 104]
[1.53 x 10-6]
+
2.68 x 10-⁹
1.75 x 10"
[1.75 × 10³]
[2.68 × 10-¹²]
2 F (aq)
1.75 x 10"
1.75 x 10"
RESET
-0.0110
[0.0110]²
7.18 x 10-18
RESET
[8.76 x 10-1²
[1.53 x 10-61²
Transcribed Image Text:Determine the value of Ksp for SrF₂ by constructing an ICE table, writing the solubility constant expression, and solving the expression. Complete Parts 1-2 before submitting your answer. NEXT > It is found that up to 0.0110 g of SrF₂ dissolves in 100 mL of aqueous solution at a certain temperature. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products at this temperature. Initial (M) Change (M) Equilibrium (M) 0 0.0110 8.76 x 10-5 -8.76 x 10-5 -8.76 x 10-4 -1.75 x 10-4 -1.75 x 10™³ [0] [8.76 x 10-¹1² SrF₂(s) 8.76 x 10-4 -8.76 x 10-4 [0.0110] 0 Ksp = [8.76 x 104] [1.75 × 10-³² [8.76 x 10-5] [1.75 x 10-41² [1.75 x 10-¹² Sr²+ (aq) [0] 8.76 x 10-4 -8.76 x 10-4 8.76 x 10-4 [8.76 x 104] 2.68 x 10-⁹ Determine the value of Ksp for SrF₂ by constructing an ICE table, writing the solubility constant expression, and solving the expression. Complete Parts 1-2 before submitting your answer. 2 < PREV 1 2 Using the values from the ICE table, construct the expression for the solubility constant. Each reaction participant must be represented by one tile. Do not combine terms Once the expression is constructed, solve for Ksp. 1.75 x 10-4 [1.75 x 104] [1.53 x 10-6] + 2.68 x 10-⁹ 1.75 x 10" [1.75 × 10³] [2.68 × 10-¹²] 2 F (aq) 1.75 x 10" 1.75 x 10" RESET -0.0110 [0.0110]² 7.18 x 10-18 RESET [8.76 x 10-1² [1.53 x 10-61²
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