Determine the truth value of [(p → q) v (q → r)] ^ (r → s) when p and q and r are False, and s is True.
Determine the truth value of [(p → q) v (q → r)] ^ (r → s) when p and q and r are False, and s is True.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Determine the truth value of \([(p \rightarrow q) \lor (q \rightarrow r)] \land (r \rightarrow s)\) when \(p\) and \(q\) and \(r\) are False, and \(s\) is True.**
- [ ] True
- [ ] False
---
To solve this, let's break it down step by step considering the given truth values:
1. Evaluate \(p \rightarrow q\):
- Since both \(p\) and \(q\) are False, \(p \rightarrow q\) is True (as False implies anything).
2. Evaluate \(q \rightarrow r\):
- Since both \(q\) and \(r\) are False, \(q \rightarrow r\) is True (as False implies anything).
3. Now, evaluate \((p \rightarrow q) \lor (q \rightarrow r)\):
- Both components are True, so the disjunction \((p \rightarrow q) \lor (q \rightarrow r)\) is True.
4. Evaluate \(r \rightarrow s\):
- Since \(r\) is False and \(s\) is True, \(r \rightarrow s\) is True (as False implies anything).
5. Finally, evaluate \([(p \rightarrow q) \lor (q \rightarrow r)] \land (r \rightarrow s)\):
- Both components are True, so the conjunction \([(p \rightarrow q) \lor (q \rightarrow r)] \land (r \rightarrow s)\) is True.
Therefore, the truth value of the given expression is:
- [x] True
- [ ] False](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92664a72-5e56-42ce-9287-433ae5912718%2F8f8e58d7-e859-4aca-9081-927ce5a9593d%2Fqo38apo_processed.png&w=3840&q=75)
Transcribed Image Text:**Determine the truth value of \([(p \rightarrow q) \lor (q \rightarrow r)] \land (r \rightarrow s)\) when \(p\) and \(q\) and \(r\) are False, and \(s\) is True.**
- [ ] True
- [ ] False
---
To solve this, let's break it down step by step considering the given truth values:
1. Evaluate \(p \rightarrow q\):
- Since both \(p\) and \(q\) are False, \(p \rightarrow q\) is True (as False implies anything).
2. Evaluate \(q \rightarrow r\):
- Since both \(q\) and \(r\) are False, \(q \rightarrow r\) is True (as False implies anything).
3. Now, evaluate \((p \rightarrow q) \lor (q \rightarrow r)\):
- Both components are True, so the disjunction \((p \rightarrow q) \lor (q \rightarrow r)\) is True.
4. Evaluate \(r \rightarrow s\):
- Since \(r\) is False and \(s\) is True, \(r \rightarrow s\) is True (as False implies anything).
5. Finally, evaluate \([(p \rightarrow q) \lor (q \rightarrow r)] \land (r \rightarrow s)\):
- Both components are True, so the conjunction \([(p \rightarrow q) \lor (q \rightarrow r)] \land (r \rightarrow s)\) is True.
Therefore, the truth value of the given expression is:
- [x] True
- [ ] False
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