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Determine the time to ignite a ½-inch particleboard subject to a flame heat flux of 25 kW/m2 with a starting temperature of 25°C. Particleboard: T = 412°C kọc = 0.93 (kW/m²K}²s %3D

Determine the time to ignite a ½-inch particleboard subject to a flame heat flux of 25 kW/m2 with a starting temperature of 25°C. Particleboard: T = 412°C kọc = 0.93 (kW/m²K}²s %3D

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Determine the time to ignite a ½-inch particleboard subject to a flame heat flux of 25 kW/m² with a starting temperature of 25°C. Particleboard: T = 412°C kọc = 0.93 (kW/m²K)?s
Transcribed Image Text:Determine the time to ignite a ½-inch particleboard subject to a flame heat flux of 25 kW/m² with a starting temperature of 25°C. Particleboard: T = 412°C kọc = 0.93 (kW/m²K)?s
Expert Solution
Step 1

Write the expression for the time to ignition as follows:

tig = π4kρcTig-T0q2    ......1

 

Given, 

Heat flux, q = 25 kW/m2

kρc = 0.93 kWm2K21s

initial temperature,

 T0 = 25 °C= 25+273 K= 298 K

 

Ignition temperature,

Tig = 412 °C= 412+273 K=685 K

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