Determine the subtransient fault current in per-unit and in kA, as well as the per-unit line-to-ground voltages at the fault bus for a bolted single line-to-ground fault at the fault bus selected in Problem 9.2. Repeat Problem 9.14 for a bolted double line-to-ground fault.
Determine the subtransient fault current in per-unit and in kA, as well as the per-unit line-to-ground voltages at the fault bus for a bolted single line-to-ground fault at the fault bus selected in Problem 9.2. Repeat Problem 9.14 for a bolted double line-to-ground fault.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
Only need answers for the second question(9.17) at bus 1.

Transcribed Image Text:9.14 Determine the subtransient fault current in per-unit and in kA, as well as the per-unit
line-to-ground voltages at the fault bus for a bolted single line-to-ground fault at the
fault bus selected in Problem 9.2.
9.17
Repeat Problem 9.14 for a bolted double line-to-ground fault.

Transcribed Image Text:The single-line diagram of a three-phase power system is shown in Figure 9.17.
Equipment ratings are given as follows:
Synchronous generators:
G1 1000 MVA
15 kV
1000 MVA
G2
G3 500 MVA
15 kV
13.8 kV
13.8 kV
G4 750 MVA
Transformers:
T1 1000 MVA
T2 1000 MVA
T3 500 MVA
T4 750 MVA
SYMMETRICAL FAULTS
Line 1-2
Transmission lines:
1-2 765 kV
1-3 765 kV
2-3 765 kV
15 kV A/765 kV Y
15 kV A/765 kV Y
15 kV Y/765 kV Y
15 kV Y/765 kV Y
₁²
◄
Line 1-3
2
2
X = X₂ = 0.18, Xo = 0.07 per unit
X = X₂ = 0.20, Xo = 0.10 per unit
X = X₂ = 0.15, Xo = 0.05 per unit
X = 0.30, X₂ = 0.40, Xo = 0.10 per unit
T₂
Line 2-3
X₁ = 50 £2, Xo = 150 2
X₁ = 40 92, Xo = 100 2
X₁ = 40 92, Xo = 100 2
X = 0.10 per unit
X = 0.10 per unit
X = 0.12 per unit
X = 0.11 per unit
3 T3
T₁
4
youthy
Expert Solution

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Step 1: Given
VIEWStep 2: Per unit reactances for generators
VIEWStep 3: Per unit reactances for transformer and tranmission lines
VIEWStep 4: Sequence network
VIEWStep 5: Fault current in per unit
VIEWStep 6: Sub transient fault current in pu and KA
VIEWStep 7: Line to ground voltages at the fault bus
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