b) Figure 4 shows a transmission line circuit using a 100 m long, low-loss 50 line of phase velocity 2.03 × 108 m/s, with a shunt 1000 load located 40 m from its source end (the far end of the 500 line, to the right, is not shown). 1 kV 5002 Zo = 5002 40 m Figure 4 Zo = 5002 10002 c) The far end of the 500 line (not shown in Figure 4, to the right) is terminated with a 2000 load, a distance of 60 m from the 1000 shunt load. Calculate: (i) The voltage and current of the 2002 end load the instant the signal arrives. (ii) The steady-state voltages and currents of the 1000 and 2000 loads.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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b) Figure 4 shows a transmission line circuit using a 100 m long, low-loss 50 line
of phase velocity 2.03 × 108 m/s, with a shunt 1000 load located 40 m from its
source end (the far end of the 500 line, to the right, is not shown).
1 kV
5002
Zo = 5002
40 m
Figure 4
Zo = 5002
10002
Transcribed Image Text:b) Figure 4 shows a transmission line circuit using a 100 m long, low-loss 50 line of phase velocity 2.03 × 108 m/s, with a shunt 1000 load located 40 m from its source end (the far end of the 500 line, to the right, is not shown). 1 kV 5002 Zo = 5002 40 m Figure 4 Zo = 5002 10002
c)
The far end of the 500 line (not shown in Figure 4, to the right) is terminated
with a 2000 load, a distance of 60 m from the 1000 shunt load. Calculate:
(i) The voltage and current of the 2002 end load the instant the signal arrives.
(ii) The steady-state voltages and currents of the 1000 and 2000 loads.
Transcribed Image Text:c) The far end of the 500 line (not shown in Figure 4, to the right) is terminated with a 2000 load, a distance of 60 m from the 1000 shunt load. Calculate: (i) The voltage and current of the 2002 end load the instant the signal arrives. (ii) The steady-state voltages and currents of the 1000 and 2000 loads.
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