Determine the structure of the compound below. C10H1402 IR shows carbonyl and ether stretches. The compound is non-aromatic. 2H 24 2H 96 t heptet 1H 1. PPM 2 3H GH 6H

C6H12O6 is the chemical formula for a ________. polymer of carbohydrate pentose monosaccharide hexose monosaccharide all of the above

The synthetic process by which monomers are covalently linked is (a) hydrolysis (b) isomerization (c) condensation (d) glycosidic linkage (e) ester linkage

VISUALIZE The structures depicted are (a) enantiomers (b) different views of the same molecule (c) geometric (cistrans) isomers (d) both geometric isomers and enantiomers (e) structural isomers