Determine the stress in the Aluminum rod (Psi) after the load 68 (kips) is applied. The light rigid bar ABCD is pinned at 8 and connected to two vertical rods. Assuming that the bar was initially horizontal and the rods stress-free.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Determine the stress in the Aluminum rod (Psi) after the load 68 (kips) is applied. The light rigid bar ABCD is pinned at 8 and connected to two vertical rods. Assuming that the bar was initially horizontal and the rods stress-free.
Steel
L = 3 ft
A = 0.5 in?
E = 29 x 10° psi
- 4 ft
B
A
D
Aluminum
L= 4 ft
A = 0.75 in
E = 10 x 10° psi
2 ft - 2 ft -→
a =48335
b. =41535
O c -55135
d. =67375
e =56155
O f. =57855
O g. =53775
Oh =61935
Transcribed Image Text:Steel L = 3 ft A = 0.5 in? E = 29 x 10° psi - 4 ft B A D Aluminum L= 4 ft A = 0.75 in E = 10 x 10° psi 2 ft - 2 ft -→ a =48335 b. =41535 O c -55135 d. =67375 e =56155 O f. =57855 O g. =53775 Oh =61935
(CLO 1, 2)Determine the stress in the Aluminum rod (Psi) after the load 68 (kips) is applied. The light rigid bar ABCD is pinned at B and connected to two vertical rods. Assuming that the bar was initially horizontal and the rods
stress-free.
Steel
L= 3 ft
A = 0.5 in?
E = 29 x 10° psi
4 ft
B
C
D
Aluminum
L= 4 ft
A = 0.75 in?
E = 10 x 10° psi
2 ft 2 ft →
O a =48335
O b. =41535
Oc =55135
O d. =67375
O e =56155
O f. =57855
Og =53775
Oh =61935
Transcribed Image Text:(CLO 1, 2)Determine the stress in the Aluminum rod (Psi) after the load 68 (kips) is applied. The light rigid bar ABCD is pinned at B and connected to two vertical rods. Assuming that the bar was initially horizontal and the rods stress-free. Steel L= 3 ft A = 0.5 in? E = 29 x 10° psi 4 ft B C D Aluminum L= 4 ft A = 0.75 in? E = 10 x 10° psi 2 ft 2 ft → O a =48335 O b. =41535 Oc =55135 O d. =67375 O e =56155 O f. =57855 Og =53775 Oh =61935
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