determine the stress in section AC of the member. The member has a cross sectional area of 0.75 [m2]. Units taken as [kPa]; do not report units in your answer e of significant digits is not P=30.0 [kN] L = 3.25 [m] A L/2 C L B

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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### Problem Description

Determine the stress in section **AC** of the member. The member has a cross-sectional area of \( 0.75 \, \text{m}^2 \). Units are in \([ \text{kPa} ]\). 

**Given:**
- \( P = 30.0 \, \text{kN} \)
- \( L = 3.25 \, \text{m} \)

### Diagram Explanation

The diagram illustrates a horizontal member that is fixed at two ends, points **A** and **B**. A load \( P \) is applied horizontally from left to right. The member's total length is divided into two segments:
- From **A** to point **C** is \( L/2 \).
- From **C** to **B** is \( L \).

**Notation:**
- \( L/2 \) indicates half the length of \( L \) from **A** to **C**.
- \( L \) indicates the distance from **C** to **B**.

The load \( P \) acts towards point **B** starting from the right of **C**, creating tension in section **AC** of the member.
Transcribed Image Text:### Problem Description Determine the stress in section **AC** of the member. The member has a cross-sectional area of \( 0.75 \, \text{m}^2 \). Units are in \([ \text{kPa} ]\). **Given:** - \( P = 30.0 \, \text{kN} \) - \( L = 3.25 \, \text{m} \) ### Diagram Explanation The diagram illustrates a horizontal member that is fixed at two ends, points **A** and **B**. A load \( P \) is applied horizontally from left to right. The member's total length is divided into two segments: - From **A** to point **C** is \( L/2 \). - From **C** to **B** is \( L \). **Notation:** - \( L/2 \) indicates half the length of \( L \) from **A** to **C**. - \( L \) indicates the distance from **C** to **B**. The load \( P \) acts towards point **B** starting from the right of **C**, creating tension in section **AC** of the member.
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