determine the stress in section AC of the member. The member has a cross sectional area of 0.75 [m2]. Units taken as [kPa]; do not report units in your answer e of significant digits is not P=30.0 [kN] L = 3.25 [m] A L/2 C L B
determine the stress in section AC of the member. The member has a cross sectional area of 0.75 [m2]. Units taken as [kPa]; do not report units in your answer e of significant digits is not P=30.0 [kN] L = 3.25 [m] A L/2 C L B
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Problem Description
Determine the stress in section **AC** of the member. The member has a cross-sectional area of \( 0.75 \, \text{m}^2 \). Units are in \([ \text{kPa} ]\).
**Given:**
- \( P = 30.0 \, \text{kN} \)
- \( L = 3.25 \, \text{m} \)
### Diagram Explanation
The diagram illustrates a horizontal member that is fixed at two ends, points **A** and **B**. A load \( P \) is applied horizontally from left to right. The member's total length is divided into two segments:
- From **A** to point **C** is \( L/2 \).
- From **C** to **B** is \( L \).
**Notation:**
- \( L/2 \) indicates half the length of \( L \) from **A** to **C**.
- \( L \) indicates the distance from **C** to **B**.
The load \( P \) acts towards point **B** starting from the right of **C**, creating tension in section **AC** of the member.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c49c29d-b734-4891-8a07-7c122a77a78d%2Faa4138fd-b5ac-4ae0-abe2-d48f90aae6c8%2Fhhygy1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Description
Determine the stress in section **AC** of the member. The member has a cross-sectional area of \( 0.75 \, \text{m}^2 \). Units are in \([ \text{kPa} ]\).
**Given:**
- \( P = 30.0 \, \text{kN} \)
- \( L = 3.25 \, \text{m} \)
### Diagram Explanation
The diagram illustrates a horizontal member that is fixed at two ends, points **A** and **B**. A load \( P \) is applied horizontally from left to right. The member's total length is divided into two segments:
- From **A** to point **C** is \( L/2 \).
- From **C** to **B** is \( L \).
**Notation:**
- \( L/2 \) indicates half the length of \( L \) from **A** to **C**.
- \( L \) indicates the distance from **C** to **B**.
The load \( P \) acts towards point **B** starting from the right of **C**, creating tension in section **AC** of the member.
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