An electric winch is being used to help construct your facility. The winch operates at 71% efficiency with an input voltage of 120 volts [V]. When the winch lifts an object to a height of 7 meters [m] in 25 seconds [s], a current of 21 amperes [A] is required. What is the approximate weight of the object the winch lifted in units of newtons [N]? Click the icon to view the table of common derived units in the SI system. The weight is 6300 N. (Round your answer to a whole number.)

An electric winch is being used to help construct your facility. The winch operates at 71% efficiency with an input voltage of 120 volts [V]. When the winch lifts an object to a height of 7 meters [m] in 25 seconds [s], a current of 21 amperes [A] is required. What is the approximate weight of the object the winch lifted in units of newtons [N]? Click the icon to view the table of common derived units in the SI system. The weight is 6300 N. (Round your answer to a whole number.)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

5
Part III Capstone Problem Interactive Physics - [Lab7Part3.IP] Eile Edit World View Object Define Measure Script Window Help Run StoplI Reset 圖|& 品凸? Time Length of Spring 22 6.00 dx Center of Mass of Rectangle 2 5.000 Tension of Rope 3 Jain@ IFI ... N ot rot ***lad Split 4.000 Velocity of Center of Mass of Rectangle 2 Vx Vx V Vy MM Ve - m/s m/s 3.00 *** m/s Vo ..* lad/s 2 00 Center of Mass of Rectangle 1 1.000 tol rot *.* rad EVelocity of Center of Mass of Rectangle 1 Vx Vx VVy M 0.000 -m/s w 30 m/s w.. MI Ve 母100 *** m/s Vo ... rad/s + EAcceleration of Center of Mass of Rectangle 1 Ax Ax A Ay AUJAI Ae --- m/s^2 ... m/s^2 -- m/s^2 .-- rad/s^2 3.00 Aø Mass M1 = 2.25 kg is at the end of a rope that is 2.00 m in length. The initial angle with respect to the vertical is 60.0° and M1 is initially at rest. Mass M1 is released and strikes M2 = 4.50 kg exactly horizontally. The collision is elastic. After collision, mass M2 is moving on a frictionless surface, but runs into a rough patch 2.00…
Engr 215 Matlab Fahrenheit to Celsius using multiple statements Given a Fahrenheit value temperatureFahrenheit, write a statement that assigns temperatureCelsius with the equivalent Celsius value. While the equation is C = 5/9 * (F - 32), as an exercise use two statements, the first of which is "fractionalMultiplier = 5/9;"]
I need help with a MATLAB code. I need to find two values of n, one that is positive and one that is negative, that will give all negative real roots. Can you help me find them? function [r] = find_roots(n) % Define constants I = 400; J = 150; x = (J/I) - 1; y = n - 1; Q = y + x*(y-1); % Define the coefficients of the quadratic equation coefficients = [1, 0, (3*x+Q^2+1), 0, (3*x*Q+Q^2)]; % Find the roots r = roots(coefficients); end
help please!!
sample calculations 目 File Edit View Insert Format Data To 100% $ % .0 .00 12: fx | A 1 Variable Value Units diameter height m 4 volume m^3 3 The image above shows a section of a Google sheet. What formula should be written in cell B4 to calculate the volume of a cylinder with a diameter value in B2 and height in B3? a) =0.25*PI()*B2^2 * B3 b) =PI()*B2^2 * B3 c) =pi*diameter^2 * height d) =PI*B2^2 * B3 3 5
Motiyo Add explanation
Your choices from the drop down menu are "1, 2.5, and 3.5" Please see both images for reference. Thanks!
I need help with my MATLAB code. There is an error in the following code. The error says my orbitaldynamics function must return a column vector. Can you help me fix it? I tried changing the semi colon to a comma in dstate_dt = [v, a_total]; but it still gives me error mu_earth = 398600.4418; % Earth's gravitational parameter (km^3/s^2) R_earth = 6378.137; % Earth's radius (km) C_d = 0.3; % Drag coefficient (assumed) A = 0.023; % Cross-sectional area of ISS (km^2) m = 420000; % Mass of ISS (kg) % Initial conditions: position and velocity (ISS state vector) % ISS initial state vector (km and km/s) - sample data state_ISS =[-2.1195e+03, 3.9866e+03, 5.0692e+03, -5.3489, -5.1772, 1.8324]; % Time span for 10 revolutions T_orbit = 2 * pi * sqrt((norm(state_ISS(1:3))^3) / mu_earth); time_span = [0, 10 * T_orbit]; % Step 3: Numerical integration using ODE solver options = odeset('RelTol', 1e-12, 'AbsTol', 1e-12); [t, state] = ode45(@orbitalDynamics, time_span, state_ISS,…
I need help coding in MATLAB. I have a .txt file containing the following data. That data is saved in a file named data.txt. I am wondering how I could extract all or some of that data into another .m file. Can you show me the code. [[5.0018696581196584, 17.863820207570207, -13.086858974358975], [5.0018696581196584, 17.863820207570207, -13.086858974358975], [5.0018696581196584, 17.863820207570207, -13.086858974358975]]
⦁ “God himself could not sink this ship” This is an advertisement for the Titanic, produced in the early 1900s. However, after colliding with an iceberg at dawn on April 15, 1912, two rivers were formed, and out of the 2,200 people on board, 1,500 people, including the captain, sank with the ship. According to a later investigation, the “temperature change theory” (DBTT theory) was the most promising cause of the sinking. Give a brief guess of the cause of the ship's sinking in relation to temperature.
For the Following question Graph all 4 : [I just need all 4 graphs and please explain and make clean solution] Position vs time Velocity vs time Acceleration vs time Force vs time [For your convenience, I have solved the numerical solutions for the problem] (Please Look at the picture since it is much cleaner) Question : A 550 kilogram mass initially at rest acted upon by a force of F(t) = 50et Newtons. What are the acceleration, speed, and displacement of the mass at t = 4 second ? a =(50 e^t)/(550 ) [N/kg] v = ∫_0^t▒(50 e^t )dt/(550 )= v_0 +(50 e^t-50)/550=((e^t- 1))/11 x = ∫_0^t▒(e^t- 1)dt/(11 )= x_0 +(e^t- t - 1)/(11 ) a(4s)=(50*54.6)/550= 4.96[m/s^2 ] v(4s)=((e^4-1))/11= 4.87[m/s] x(4s)=((e^4- 4 - 1))/11= 4.51 [m]