Determine the stress in a fiber (in psi) located 1inch from the top of the beam and 4 feet from the hinge. Refer to the illustrative example in the image below.
Determine the stress in a fiber (in psi) located 1inch from the top of the beam and 4 feet from the hinge. Refer to the illustrative example in the image below.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Determine the stress in a fiber (in psi) located 1inch from the top of the beam and 4 feet from the hinge.
Refer to the illustrative example in the image below.
![Flexure Formula
Example
A simply supported beam, 2 in wide by 4 in high and 12 ft long is subjected to a concentrated load of
2000 lb at a point 3 ft from one of the supports. Determine the maximum fiber stress and the stress in
a fiber located 0.5 in from the top of the beam at midspan.
EMR2 = 0
12R₁ = 9(2000)
R₁ = 1500 lb
EMRI = 0
12R₂ = 3(2000)
R₂ = 500 lb
Maximum fiber stress:
c = 2 in
(fb)mar
N.A.
Mm
6
b = 2 in
(fb)maz 10, 125 psi
=
fb =
Me
I
fb
Mm 3000 lb-ft
My
I
4500(12) (2)
2(4³)
12
b= 4 in
3000(12)(1.5)
2(4³)
12
fb = 5,062.5 psi
answer
R₁
answer
2000 lb
: 1500 lb
Stress in a fiber located 0.5 in from the top of the beam at mid-span
4500
9
0.5 in
y = 1.5 in
3 ft
N.A.
12 ft
4500 lb-ft
b = 2 in
Shear Diagram
Mm
9 ft
-500 lb
Moment Diagram
b=4 in
R₂](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8750e0f5-82da-4664-a20a-6e5b01f9e1dc%2F21e2af68-58c1-4eca-916f-8bb4b7b07adc%2Fky4866o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Flexure Formula
Example
A simply supported beam, 2 in wide by 4 in high and 12 ft long is subjected to a concentrated load of
2000 lb at a point 3 ft from one of the supports. Determine the maximum fiber stress and the stress in
a fiber located 0.5 in from the top of the beam at midspan.
EMR2 = 0
12R₁ = 9(2000)
R₁ = 1500 lb
EMRI = 0
12R₂ = 3(2000)
R₂ = 500 lb
Maximum fiber stress:
c = 2 in
(fb)mar
N.A.
Mm
6
b = 2 in
(fb)maz 10, 125 psi
=
fb =
Me
I
fb
Mm 3000 lb-ft
My
I
4500(12) (2)
2(4³)
12
b= 4 in
3000(12)(1.5)
2(4³)
12
fb = 5,062.5 psi
answer
R₁
answer
2000 lb
: 1500 lb
Stress in a fiber located 0.5 in from the top of the beam at mid-span
4500
9
0.5 in
y = 1.5 in
3 ft
N.A.
12 ft
4500 lb-ft
b = 2 in
Shear Diagram
Mm
9 ft
-500 lb
Moment Diagram
b=4 in
R₂
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