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Determine the stress in a fiber (in psi) located 1inch from the top of the beam and 4 feet from the hinge. Refer to the illustrative example in the image below.

Determine the stress in a fiber (in psi) located 1inch from the top of the beam and 4 feet from the hinge. Refer to the illustrative example in the image below.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Determine the stress in a fiber (in psi) located 1inch from the top of the beam and 4 feet from the hinge. Refer to the illustrative example in the image below.
Flexure Formula Example A simply supported beam, 2 in wide by 4 in high and 12 ft long is subjected to a concentrated load of 2000 lb at a point 3 ft from one of the supports. Determine the maximum fiber stress and the stress in a fiber located 0.5 in from the top of the beam at midspan. EMR2 = 0 12R₁ = 9(2000) R₁ = 1500 lb EMRI = 0 12R₂ = 3(2000) R₂ = 500 lb Maximum fiber stress: c = 2 in (fb)mar N.A. Mm 6 b = 2 in (fb)maz 10, 125 psi = fb = Me I fb Mm 3000 lb-ft My I 4500(12) (2) 2(4³) 12 b= 4 in 3000(12)(1.5) 2(4³) 12 fb = 5,062.5 psi answer R₁ answer 2000 lb : 1500 lb Stress in a fiber located 0.5 in from the top of the beam at mid-span 4500 9 0.5 in y = 1.5 in 3 ft N.A. 12 ft 4500 lb-ft b = 2 in Shear Diagram Mm 9 ft -500 lb Moment Diagram b=4 in R₂
Transcribed Image Text:Flexure Formula Example A simply supported beam, 2 in wide by 4 in high and 12 ft long is subjected to a concentrated load of 2000 lb at a point 3 ft from one of the supports. Determine the maximum fiber stress and the stress in a fiber located 0.5 in from the top of the beam at midspan. EMR2 = 0 12R₁ = 9(2000) R₁ = 1500 lb EMRI = 0 12R₂ = 3(2000) R₂ = 500 lb Maximum fiber stress: c = 2 in (fb)mar N.A. Mm 6 b = 2 in (fb)maz 10, 125 psi = fb = Me I fb Mm 3000 lb-ft My I 4500(12) (2) 2(4³) 12 b= 4 in 3000(12)(1.5) 2(4³) 12 fb = 5,062.5 psi answer R₁ answer 2000 lb : 1500 lb Stress in a fiber located 0.5 in from the top of the beam at mid-span 4500 9 0.5 in y = 1.5 in 3 ft N.A. 12 ft 4500 lb-ft b = 2 in Shear Diagram Mm 9 ft -500 lb Moment Diagram b=4 in R₂
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