Determine the steady-state current i(t) in the circuits below:

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Hi please help the image is attached below. Thank you.

**Determine the steady-state current \( i(t) \) in the circuits below:**

(Here, include any images or diagrams of the circuits in question. Ensure they are clearly labeled for students to reference as they learn about steady-state currents.)

Explanation:
- **i(t)**: This denotes the current as a function of time \( t \).
- **Steady-state current**: The current after a long period, when all transient effects have died out and the system is in equilibrium.
  
To determine the steady-state current:
1. Identify the components in the circuit (resistors, capacitors, inductors, etc.).
2. Apply Ohm's Law \( V = IR \) where applicable.
3. Use Kirchhoff's Voltage and Current Laws for complex circuits.
4. Solve the resulting equations for \( i(t) \).

Graphs/Diagrams:
- If a diagram includes resistors, capacitors, and inductors, label them with their respective symbols (R for resistors, C for capacitors, and L for inductors).
- If there is a graph depicting current over time, label the axes (Time \( t \) on the x-axis and Current \( i(t) \) on the y-axis).

For further study, refer to our detailed module on analyzing electrical circuits to understand the principles behind steady-state currents in various configurations.
Transcribed Image Text:**Determine the steady-state current \( i(t) \) in the circuits below:** (Here, include any images or diagrams of the circuits in question. Ensure they are clearly labeled for students to reference as they learn about steady-state currents.) Explanation: - **i(t)**: This denotes the current as a function of time \( t \). - **Steady-state current**: The current after a long period, when all transient effects have died out and the system is in equilibrium. To determine the steady-state current: 1. Identify the components in the circuit (resistors, capacitors, inductors, etc.). 2. Apply Ohm's Law \( V = IR \) where applicable. 3. Use Kirchhoff's Voltage and Current Laws for complex circuits. 4. Solve the resulting equations for \( i(t) \). Graphs/Diagrams: - If a diagram includes resistors, capacitors, and inductors, label them with their respective symbols (R for resistors, C for capacitors, and L for inductors). - If there is a graph depicting current over time, label the axes (Time \( t \) on the x-axis and Current \( i(t) \) on the y-axis). For further study, refer to our detailed module on analyzing electrical circuits to understand the principles behind steady-state currents in various configurations.
### Educational Resource: Electrical Circuit Analysis

#### Circuit Diagram Description:

This circuit consists of:
1. **AC Voltage Source**: Represented by a sinusoidal waveform symbol, the voltage source provides an alternating current (AC) voltage defined by the function \( v(t) = 80 \cos (200t) \).
2. **Capacitor**: Labeled as \( C \) with a capacitance value of \( 100 \mu F \) (microfarads).
3. **Current Flow**: Indicated by the red arrow representing \( i(t) \), which is the current flowing through the circuit.

#### Detailed Description:

- **Voltage Source \( v(t) \)**: The voltage source in this circuit provides a time-varying voltage given by the equation \( v(t) = 80 \cos (200t) \). This equation describes an AC voltage with an amplitude of 80 volts and a frequency defined by the term \( 200t \), indicating the angular frequency is 200 radians per second.

- **Capacitor \( C \)**: The circuit includes a capacitor with a capacitance of \( 100 \mu F \). The capacitor stores energy in the form of an electric field and its behavior in the circuit depends on the frequency of the applied AC voltage.

- **Current \( i(t) \)**: The red arrow indicates the direction of the current \( i(t) \) that flows in response to the applied voltage \( v(t) \).

#### Explanation of the Circuit Operation:

When an AC voltage is applied across a capacitor, the current \( i(t) \) leads the voltage \( v(t) \) by 90 degrees (π/2 radians) in phase. This leading current is a characteristic behavior of capacitors in AC circuits. 

The relationship of the current \( i(t) \) to the voltage \( v(t) \) in a purely capacitive circuit is given by:

\[ i(t) = C \frac{dv(t)}{dt} \]

Given the voltage \( v(t) = 80 \cos (200t) \):

1. Calculate the derivative of \( v(t) \):
\[ \frac{dv(t)}{dt} = 80 \cdot (-200) \sin(200t) = -16000 \sin(200t) \]

2. Multiply by the capacitance \( C \):
\[ i(t) = 100
Transcribed Image Text:### Educational Resource: Electrical Circuit Analysis #### Circuit Diagram Description: This circuit consists of: 1. **AC Voltage Source**: Represented by a sinusoidal waveform symbol, the voltage source provides an alternating current (AC) voltage defined by the function \( v(t) = 80 \cos (200t) \). 2. **Capacitor**: Labeled as \( C \) with a capacitance value of \( 100 \mu F \) (microfarads). 3. **Current Flow**: Indicated by the red arrow representing \( i(t) \), which is the current flowing through the circuit. #### Detailed Description: - **Voltage Source \( v(t) \)**: The voltage source in this circuit provides a time-varying voltage given by the equation \( v(t) = 80 \cos (200t) \). This equation describes an AC voltage with an amplitude of 80 volts and a frequency defined by the term \( 200t \), indicating the angular frequency is 200 radians per second. - **Capacitor \( C \)**: The circuit includes a capacitor with a capacitance of \( 100 \mu F \). The capacitor stores energy in the form of an electric field and its behavior in the circuit depends on the frequency of the applied AC voltage. - **Current \( i(t) \)**: The red arrow indicates the direction of the current \( i(t) \) that flows in response to the applied voltage \( v(t) \). #### Explanation of the Circuit Operation: When an AC voltage is applied across a capacitor, the current \( i(t) \) leads the voltage \( v(t) \) by 90 degrees (π/2 radians) in phase. This leading current is a characteristic behavior of capacitors in AC circuits. The relationship of the current \( i(t) \) to the voltage \( v(t) \) in a purely capacitive circuit is given by: \[ i(t) = C \frac{dv(t)}{dt} \] Given the voltage \( v(t) = 80 \cos (200t) \): 1. Calculate the derivative of \( v(t) \): \[ \frac{dv(t)}{dt} = 80 \cdot (-200) \sin(200t) = -16000 \sin(200t) \] 2. Multiply by the capacitance \( C \): \[ i(t) = 100
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