Determine the resultant of the concurrent forces in KN below. F1 = 222 KN, 01 = 59° F2 = 689 KN, 02 = 68°, F3 = 482 kN, 03 = 26°. Write numerical value only with 2 decimal places LL 0₁ 03 میرا +Y F₂ Fy + X

Q: Determine the minimum magnitude of F for which motion impends if µg = 0.3 а 58.9N c F>0 %3D b 6.00 N…

A: Calculating the minimum magnitude F: F¯=μsNF∵NF=mg=20×9.81=196.2 NF¯=0.3×196.2F¯=58.86 N≃58.9 N

Q: A rectangular gate AB hinged at A has a width 2.0 m perpendicular to the paper, has a negligible…

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Q: r= cos 8= sin 8= q/unit length 0x q/unit length 0 de P(r,0) og Ter=Tre 5. A line load of q per unit…

A: A line load q per unit length is applied at the ground surface which is shown in the above figure. q…

Q: 532

A: Let's go through the problem step-by-step to compute the horizontal reaction force at point A on…

Q: 2/14 If the equal tensions T in the pulley cable are 400 N, express in vector notation the force R…

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Q: 5 A rectangular gate AB hinged at A has a width 2.0 m perpendicular to the paper, has a negligible…

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Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.