Determine the rate law and the value of k for the following reaction using the data provided. S20g2 (aq) + 31 (aq) → 2 SO42 (g) + [S20g2 ]j (M)(I"]; (M) Initial Rate (M/s) 13 (aq) 0.30 0.42 4.54 0.44 0.42 6.65 0.44 0.21 3.33 Rate = [86 M 25-1[S20g2 112 Rate = [195 M-35-1IS2082 12(112 Rate = [23 M-1/25-1||S2082M1/2 - [36 M-15-1||520g |"] Rate = Rate = [120 M-25-1|(S20g²1?1] %3D
Determine the rate law and the value of k for the following reaction using the data provided. S20g2 (aq) + 31 (aq) → 2 SO42 (g) + [S20g2 ]j (M)(I"]; (M) Initial Rate (M/s) 13 (aq) 0.30 0.42 4.54 0.44 0.42 6.65 0.44 0.21 3.33 Rate = [86 M 25-1[S20g2 112 Rate = [195 M-35-1IS2082 12(112 Rate = [23 M-1/25-1||S2082M1/2 - [36 M-15-1||520g |"] Rate = Rate = [120 M-25-1|(S20g²1?1] %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Determine the rate law and the value of k for the following reaction using the data provided.
S20g2 (aq)
+ 3 1'(aq) → 2 SO4² (g) +
[S20g2]; (M)[I"]; (M) Initial Rate (M/s)
13 (aq)
0.30
0.42
4.54
0.44
0.42
6.65
0.44
0.21
3.33
O Rate = [86 M-2s 1[S20g2-1[17?
%3D
O Rate = [195 M-3s-1[S20g²1²{u]²
%3D
O Rate = [23 M-1/25-1][S20g²-][1]1/2
%3D
O Rate = [36 M-15-1|[S20g² 1[1']
%3D
O Rate = [120 M-2s-1][S20g2-1²{1']
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb7a6ddd6-9522-4c7e-bff1-23d6943042e2%2Ff66284d6-2a3d-4410-bc5b-f0e63c12f6c5%2Fn6tu3i5x_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the rate law and the value of k for the following reaction using the data provided.
S20g2 (aq)
+ 3 1'(aq) → 2 SO4² (g) +
[S20g2]; (M)[I"]; (M) Initial Rate (M/s)
13 (aq)
0.30
0.42
4.54
0.44
0.42
6.65
0.44
0.21
3.33
O Rate = [86 M-2s 1[S20g2-1[17?
%3D
O Rate = [195 M-3s-1[S20g²1²{u]²
%3D
O Rate = [23 M-1/25-1][S20g²-][1]1/2
%3D
O Rate = [36 M-15-1|[S20g² 1[1']
%3D
O Rate = [120 M-2s-1][S20g2-1²{1']
%3D
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