Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) 4 NO2(g) + O2(8) [N205k (M) Initial Rate (M/s) 0.093 4.84 x 10-4 0.174 9.05 x 10-4 0.224 1.16 x 10-3 Rate = 6.0 x 10-1 M-25-1IN205]3 Rate = 1.6 x 10-3 M1/25-1[N205]1/2 Rate = 5.2 x 10-3 s[N205] Rate = 1.7 x 10-2 M1/25-1[N205]3/2 Rate = 5.6 x 10-2 M15IN205]2
Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) 4 NO2(g) + O2(8) [N205k (M) Initial Rate (M/s) 0.093 4.84 x 10-4 0.174 9.05 x 10-4 0.224 1.16 x 10-3 Rate = 6.0 x 10-1 M-25-1IN205]3 Rate = 1.6 x 10-3 M1/25-1[N205]1/2 Rate = 5.2 x 10-3 s[N205] Rate = 1.7 x 10-2 M1/25-1[N205]3/2 Rate = 5.6 x 10-2 M15IN205]2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Determine the rate law and the value of k for the following reaction using the data provided.
2 N205(g) 4 NO2(8) + O2(8)
N205h (M)
Initial Rate (M/s)
0.093
4.84 x 10-4
0.174
9.05 x 10-4
0.224
1.16 x 10-3
Rate = 6.0 x 10-1 M-25-1[N20513
Rate = 1.6 x 10-3 M1/25-1[N205]1/2
Rate = 5.2 x 10-3 s[N205]
Rate = 1.7 x 10-2 M1/2s-1[N205]3/2
Rate = 5.6 x
10-2 M-151IN20512](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F39a6c793-b207-4945-b9e4-d211323cb51c%2F9cddbacd-8500-4782-befe-e14eeb524788%2Fhahs986_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the rate law and the value of k for the following reaction using the data provided.
2 N205(g) 4 NO2(8) + O2(8)
N205h (M)
Initial Rate (M/s)
0.093
4.84 x 10-4
0.174
9.05 x 10-4
0.224
1.16 x 10-3
Rate = 6.0 x 10-1 M-25-1[N20513
Rate = 1.6 x 10-3 M1/25-1[N205]1/2
Rate = 5.2 x 10-3 s[N205]
Rate = 1.7 x 10-2 M1/2s-1[N205]3/2
Rate = 5.6 x
10-2 M-151IN20512
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