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Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) 4 NO2(g) + O2(8) [N205k (M) Initial Rate (M/s) 0.093 4.84 x 10-4 0.174 9.05 x 10-4 0.224 1.16 x 10-3 Rate = 6.0 x 10-1 M-25-1IN205]3 Rate = 1.6 x 10-3 M1/25-1[N205]1/2 Rate = 5.2 x 10-3 s[N205] Rate = 1.7 x 10-2 M1/25-1[N205]3/2 Rate = 5.6 x 10-2 M15IN205]2

Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) 4 NO2(g) + O2(8) [N205k (M) Initial Rate (M/s) 0.093 4.84 x 10-4 0.174 9.05 x 10-4 0.224 1.16 x 10-3 Rate = 6.0 x 10-1 M-25-1IN205]3 Rate = 1.6 x 10-3 M1/25-1[N205]1/2 Rate = 5.2 x 10-3 s[N205] Rate = 1.7 x 10-2 M1/25-1[N205]3/2 Rate = 5.6 x 10-2 M15IN205]2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) 4 NO2(8) + O2(8) N205h (M) Initial Rate (M/s) 0.093 4.84 x 10-4 0.174 9.05 x 10-4 0.224 1.16 x 10-3 Rate = 6.0 x 10-1 M-25-1[N20513 Rate = 1.6 x 10-3 M1/25-1[N205]1/2 Rate = 5.2 x 10-3 s[N205] Rate = 1.7 x 10-2 M1/2s-1[N205]3/2 Rate = 5.6 x 10-2 M-151IN20512
Transcribed Image Text:Determine the rate law and the value of k for the following reaction using the data provided. 2 N205(g) 4 NO2(8) + O2(8) N205h (M) Initial Rate (M/s) 0.093 4.84 x 10-4 0.174 9.05 x 10-4 0.224 1.16 x 10-3 Rate = 6.0 x 10-1 M-25-1[N20513 Rate = 1.6 x 10-3 M1/25-1[N205]1/2 Rate = 5.2 x 10-3 s[N205] Rate = 1.7 x 10-2 M1/2s-1[N205]3/2 Rate = 5.6 x 10-2 M-151IN20512
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