Determine the rate law and the value of k for the following reaction using the data provided. 2 NO(g) + 02(g) - 2 NO2(g) [NO]i (M) [02]i (M) 0.030 0.0055 0.030 0.0110 0.060 0.0055 A) Rate=57 M-1g-1 [NO][0₂] B) Rate = 3.8 M-1/2-1[NO][0₂]1/2 C) Rate = 3.1 x 105 M-³s-1 [NO]²[0₂]² D) Rate = 1.7 × 103 M-25-1 [NO]²[0₂] X E) Rate = 9.4 x 103 M-2s-1 [NO][0₂1² Initial Rate (M-1,-1) 8.55 × 10-3 1.71 × 10-2 3.42 × 10-2
Determine the rate law and the value of k for the following reaction using the data provided. 2 NO(g) + 02(g) - 2 NO2(g) [NO]i (M) [02]i (M) 0.030 0.0055 0.030 0.0110 0.060 0.0055 A) Rate=57 M-1g-1 [NO][0₂] B) Rate = 3.8 M-1/2-1[NO][0₂]1/2 C) Rate = 3.1 x 105 M-³s-1 [NO]²[0₂]² D) Rate = 1.7 × 103 M-25-1 [NO]²[0₂] X E) Rate = 9.4 x 103 M-2s-1 [NO][0₂1² Initial Rate (M-1,-1) 8.55 × 10-3 1.71 × 10-2 3.42 × 10-2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Determine the rate law and the value of k for the following reaction using the
data provided.
2 NO(g) + O2(g) → 2 NO₂(g) [NO]i (M) [0₂]i (M)
0.030
0.030
0.060
A) Rate = 57 M-1s-1 [NO][0₂]
B) Rate = 3.8 M-1/2-1[NO][0₂]¹/2
C) Rate = 3.1 x 105 M-³s-1 [NO]²[0₂]²
D) Rate = 1.7 × 103 M-2s-1 [NO]²[0₂]
E) Rate = 9.4 × 103 M-²s-1 [NO][0₂]²
0.0055
0.0110
0.0055
Initial Rate (M-1,-1)
8.55 × 10-3
1.71 × 10-2
3.42 × 10-2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c2741be-dba9-44fc-9ff6-025e89401079%2Fb174a79b-a579-4579-b2e6-61ea076a8643%2Fpr0ms0o_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the rate law and the value of k for the following reaction using the
data provided.
2 NO(g) + O2(g) → 2 NO₂(g) [NO]i (M) [0₂]i (M)
0.030
0.030
0.060
A) Rate = 57 M-1s-1 [NO][0₂]
B) Rate = 3.8 M-1/2-1[NO][0₂]¹/2
C) Rate = 3.1 x 105 M-³s-1 [NO]²[0₂]²
D) Rate = 1.7 × 103 M-2s-1 [NO]²[0₂]
E) Rate = 9.4 × 103 M-²s-1 [NO][0₂]²
0.0055
0.0110
0.0055
Initial Rate (M-1,-1)
8.55 × 10-3
1.71 × 10-2
3.42 × 10-2
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