College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
Please use the equations attached
![Fundamental Equation of Dynamics
KINAMATICS
Equations of Motion:
Particle Rectilinear motion:
Constant a = de
EF = ma
EF, = m(ag),
EF, = m(ag),
Variable a
Particle
dv
ds
v = vo + at
1
Rigid Body
(Plane Motion)
dt
s = , + vạt +at
12 = vỷ + 2a.(s - 50)
ads = vdv
EMG = Iça a EMp = E(M)p
Particle Curvilinear Motion:
Principle of Work and Energy:
T, + U,-2 = T,
Cartesian Coordinates (1,y,z)
V = * a, = *
Vy = ý ay = jỹ
Kinetic Energy
Particle
T =
: T=mvå + lgw?²
or T= 1,w?
Polar Coordinates (r,8,z)
Rigid Body
a, = # - re?
ag = rê + 2rẻ
(Plane Motion)
V = ré
Work
Uş = SF cos e de
U, = (F cos 8)As
Uw = -WAy
Variable Force :
Normal-Tangential Coordinates (n,t,b)
Constant Force:
a = i = v,
Weight
U, = -(kei -kei)
Spring
[1+ (dy/dx)*]a/2
|d²y/dx*|
Couple of Moment: UM = M AO
Where p=
Power and Efficiency
du
Uout
Pout
P = = Fv, E=
Pin
Conservation of Energy Theorem
!!
dt
Relative Motion
VB = VA + VB/A
T +V = T2 + V2
Potential Energy
Rigid Body Motion About a Fixed Axis
V = V, + V.
Where:
V = ± Wy , V, = +ks?
Иariable a
Constant a = de
Principle of linear Impulse and Momentum:
dw
w = w, +at
a =
dt
1
e = 0, + wat +
w? = w3 + 2a.(0 - 0.)
mv, +ES Fåt = mvz
Rigid Body: m(vc)ı +ES Fdt = m(va)a
Particle
de
dt
wdw = ade
For Point P
Conservation of Linear Momentum:
s= er, v= wr. a = ar, an = w'r
Σ(mv), Σ (mv),
Relative General Plane Motion-Translating
Coefficient of Restitution
(v3), – (v)2
Axes
Vg = VA + vn/Acpin) B = Ga+ aB/Apin)
Principle of Angular Impulse and Momentun:
: (H,), +ES M,dt = (H,)2
Where H, = (d)(mv)
Relative General Plane Motion-Tran. And
Rot. Axis
Particle
Vg = VA + w X TB/a + (VB/A)vz
ag = an + i x P/a +w x (w x rayA)
+ 2w x (V8/A)v
Rigid Body : (H.h +ES M,dt = (H)2
(Plane Motion)
+
Where He = Igw
Kineties
(H.)1 +
M,dt = (H,)2
Mass Moment of Inertia
Parallel-Axis Theory
1= [r*dm
1 = lg + m d?
Where H, = 1,w
Conservation of Angular Momentum
Radius of Gyration
k =
Σ(Η), Σ (Η),](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F105d00ac-cdf8-4a24-b39f-f5cba8eeae65%2F0f797320-7f58-45a2-8308-2d1cf0b48b85%2Fbiamex5_processed.png&w=3840&q=75)
Transcribed Image Text:Fundamental Equation of Dynamics
KINAMATICS
Equations of Motion:
Particle Rectilinear motion:
Constant a = de
EF = ma
EF, = m(ag),
EF, = m(ag),
Variable a
Particle
dv
ds
v = vo + at
1
Rigid Body
(Plane Motion)
dt
s = , + vạt +at
12 = vỷ + 2a.(s - 50)
ads = vdv
EMG = Iça a EMp = E(M)p
Particle Curvilinear Motion:
Principle of Work and Energy:
T, + U,-2 = T,
Cartesian Coordinates (1,y,z)
V = * a, = *
Vy = ý ay = jỹ
Kinetic Energy
Particle
T =
: T=mvå + lgw?²
or T= 1,w?
Polar Coordinates (r,8,z)
Rigid Body
a, = # - re?
ag = rê + 2rẻ
(Plane Motion)
V = ré
Work
Uş = SF cos e de
U, = (F cos 8)As
Uw = -WAy
Variable Force :
Normal-Tangential Coordinates (n,t,b)
Constant Force:
a = i = v,
Weight
U, = -(kei -kei)
Spring
[1+ (dy/dx)*]a/2
|d²y/dx*|
Couple of Moment: UM = M AO
Where p=
Power and Efficiency
du
Uout
Pout
P = = Fv, E=
Pin
Conservation of Energy Theorem
!!
dt
Relative Motion
VB = VA + VB/A
T +V = T2 + V2
Potential Energy
Rigid Body Motion About a Fixed Axis
V = V, + V.
Where:
V = ± Wy , V, = +ks?
Иariable a
Constant a = de
Principle of linear Impulse and Momentum:
dw
w = w, +at
a =
dt
1
e = 0, + wat +
w? = w3 + 2a.(0 - 0.)
mv, +ES Fåt = mvz
Rigid Body: m(vc)ı +ES Fdt = m(va)a
Particle
de
dt
wdw = ade
For Point P
Conservation of Linear Momentum:
s= er, v= wr. a = ar, an = w'r
Σ(mv), Σ (mv),
Relative General Plane Motion-Translating
Coefficient of Restitution
(v3), – (v)2
Axes
Vg = VA + vn/Acpin) B = Ga+ aB/Apin)
Principle of Angular Impulse and Momentun:
: (H,), +ES M,dt = (H,)2
Where H, = (d)(mv)
Relative General Plane Motion-Tran. And
Rot. Axis
Particle
Vg = VA + w X TB/a + (VB/A)vz
ag = an + i x P/a +w x (w x rayA)
+ 2w x (V8/A)v
Rigid Body : (H.h +ES M,dt = (H)2
(Plane Motion)
+
Where He = Igw
Kineties
(H.)1 +
M,dt = (H,)2
Mass Moment of Inertia
Parallel-Axis Theory
1= [r*dm
1 = lg + m d?
Where H, = 1,w
Conservation of Angular Momentum
Radius of Gyration
k =
Σ(Η), Σ (Η),
Transcribed Image Text:Q3
A graph of force versus time shows the forces of a girl used to push a force against a
machine as shown in the Figure Q3. While the second graph shows her am's velocity
acting in the same direction as the force varies with time.
Determine the power applied (as function of time, f).
(i)
Calculate the work done in 0.8 seconds.
(i) Determine the maximum power developed during the 0.8 seconds period.
(iv) Ifthe time of motion exceed 0.7 seconds, would she still be able to produce such
amount of power? Explain your answer.
F(N)
630
0.7
0.8
* (m/s)
25
(s)
0.8
Figure Q3
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