Determine the pH of a buffer that is 0.25 M NH3 and 0.15 M NH.CI. The value of pKb for NH3 is 4.75. 1 2 3 NEXT Based on the given values, set up ICE table in order to determine the unknown. NH:(aq) Н.О() Он (аq) NH. (aq) + + Initial (M) Change (M) Equilibrium (M) 5 RESET 0.25 0.15 4.75 +x -x +2x -2x 0.25 + x 0.25 - x 0.25 + 2x 0.25 - 2x 0.15 + x 0.15 - x 0.15 + 2x 0.15 - 2x

Determine the pH of a buffer that is 0.25 M NH3 and 0.15 M NH.CI. The value of pKb for NH3 is 4.75. 1 2 3 NEXT Based on the given values, set up ICE table in order to determine the unknown. NH:(aq) Н.О() Он (аq) NH. (aq) + + Initial (M) Change (M) Equilibrium (M) 5 RESET 0.25 0.15 4.75 +x -x +2x -2x 0.25 + x 0.25 - x 0.25 + 2x 0.25 - 2x 0.15 + x 0.15 - x 0.15 + 2x 0.15 - 2x

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Determine the pH of a buffer that is 0.25 M NH3 and 0.15 M NH.CI. The value of
pKb for NH3 is 4.75.
1
2
3
NEXT
>
Based on the given values, set up ICE table in order to determine the unknown.
NH:(aq)
H:O(1)
он (аq)
NH (aq)
+
+
Initial (M)
Change (M)
Equilibrium (M)
5 RESET
0.25
0.15
4.75
+x
-X
+2x
-2x
0.25 + x
0.25 - x
0.25 + 2x
0.25 - 2x
0.15 + x
0.15 - x
0.15 + 2x
0.15 - 2x

Determine the pH of a buffer that is 0.25 M NH3 and 0.15 M NH:CI. The value of
pKb for NH3 is 4.75.
PREV
1
3
NEXT
>
Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine
the unknown. Do not combine or simplify terms.
Kp
5 RESET
[0]
[0.25]
[0.15]
[4.75]
[x]
[2x]
[2x]?
[0.25 + x]
[0.25 - x]
[0.25 + 2x]
[0.25 - 2x]
[0.15 + x]
[О.15 - х]
[0.15 + 2x]
[0.15 - 2x]
4.75
1.78 x 10-5
5.62 x 10-10
1.79 x 10-19

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