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Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO: after 80.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 3 4 NEXT > Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ka = 5 RESET [0] [0.100] [0.200] [0.0333] [0.0667] [x] [2x] [0.100 + x] [0.100 - x] [0.200 + x] [0.200 - x] [0.0333 + x] [0.0333 - x] [0.0667 + x] [0.0667 - x] 3.0 x 106 3.0 x 10 3.3 x 109 3.3 x 107

Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO: after 80.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 3 4 NEXT > Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ka = 5 RESET [0] [0.100] [0.200] [0.0333] [0.0667] [x] [2x] [0.100 + x] [0.100 - x] [0.200 + x] [0.200 - x] [0.0333 + x] [0.0333 - x] [0.0667 + x] [0.0667 - x] 3.0 x 106 3.0 x 10 3.3 x 109 3.3 x 107

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO: after 80.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 3 4 NEXT > Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ka = 5 RESET [0] [0.100] [0.200] [0.0333] [0.0667] [x] [2x] [0.100 + x] [0.100 - x] [0.200 + x] [0.200 - x] [0.0333 + x] [0.0333 - x] [0.0667 + x] [0.0667 - x] 3.0 x 106 3.0 x 10 3.3 x 109 3.3 x 107
Transcribed Image Text:Determine the pH at the point in the titration of 40.0 mL of 0.200 M H2NNH2 with 0.100 M HNO: after 80.0 mL of the strong acid has been added. The value of Kb for H2NNH2 is 3.0 x 10-6. PREV 1 2 3 4 NEXT > Based on your ICE table and definition of Ka, set up the expression for Ka in order to determine the unknown. Do not combine or simplify terms. Ka = 5 RESET [0] [0.100] [0.200] [0.0333] [0.0667] [x] [2x] [0.100 + x] [0.100 - x] [0.200 + x] [0.200 - x] [0.0333 + x] [0.0333 - x] [0.0667 + x] [0.0667 - x] 3.0 x 106 3.0 x 10 3.3 x 109 3.3 x 107
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