Determine the number of molecules of Cr20, that form when 1.34 x 103 g of oxygen completely reacts according to the following equation: 4 Cr(s) + 3 O2(g) → 2 Cr,03(s) STARTING AMOUNT

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Chapter1: Chemical Foundations
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Determine the number of molecules of Cr,0; that form when 1.34 x 103
g of oxygen completely reacts according to the following equation:
4
Cr(s) +
3
O2(g) → 2 Cr2O3(s)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
|2.52 х 1025
152.00
4.24 x 103
|3.78 х 1025
3
1.68 х 1025
4
6.022 x 1023 1.34 x 10°
52.00
32.00
1
g O2
g Cr203
mol Cr2O3
molecules Cr203
mol Cr
g Cr
mol O2
Transcribed Image Text:Determine the number of molecules of Cr,0; that form when 1.34 x 103 g of oxygen completely reacts according to the following equation: 4 Cr(s) + 3 O2(g) → 2 Cr2O3(s) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) |2.52 х 1025 152.00 4.24 x 103 |3.78 х 1025 3 1.68 х 1025 4 6.022 x 1023 1.34 x 10° 52.00 32.00 1 g O2 g Cr203 mol Cr2O3 molecules Cr203 mol Cr g Cr mol O2
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