Determine the number of atoms of O in 57.4 moles of Al2(CO3)3.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Question 11 of 14**

**Determine the number of atoms of O in 57.4 moles of Al₂(CO₃)₃.**

This problem involves calculating the number of oxygen atoms in a given amount of moles of a chemical compound. The compound in question is Aluminum Carbonate, Al₂(CO₃)₃, which contains carbon and oxygen in its carbonate groups. 

### Explanation

- **Molecular Formula**: Al₂(CO₃)₃
  - Each molecule of Aluminum Carbonate consists of 2 aluminum atoms, 3 carbonate ions.
  - Each carbonate ion, CO₃²⁻, contains 1 carbon atom and 3 oxygen atoms.
  
- **Calculating Oxygen Atoms**:
  - In each formula unit of Al₂(CO₃)₃, there are 3 carbonate ions.
  - Therefore, there are \(3 \times 3 = 9\) oxygen atoms in each molecule of Al₂(CO₃)₃.
  - Given 57.4 moles of Al₂(CO₃)₃, the total number of moles of oxygen atoms = 57.4 moles × 9.
  - The number of atoms is found using Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole).

This type of problem is common in chemistry for practicing mole and Avogadro's number calculations.
Transcribed Image Text:**Question 11 of 14** **Determine the number of atoms of O in 57.4 moles of Al₂(CO₃)₃.** This problem involves calculating the number of oxygen atoms in a given amount of moles of a chemical compound. The compound in question is Aluminum Carbonate, Al₂(CO₃)₃, which contains carbon and oxygen in its carbonate groups. ### Explanation - **Molecular Formula**: Al₂(CO₃)₃ - Each molecule of Aluminum Carbonate consists of 2 aluminum atoms, 3 carbonate ions. - Each carbonate ion, CO₃²⁻, contains 1 carbon atom and 3 oxygen atoms. - **Calculating Oxygen Atoms**: - In each formula unit of Al₂(CO₃)₃, there are 3 carbonate ions. - Therefore, there are \(3 \times 3 = 9\) oxygen atoms in each molecule of Al₂(CO₃)₃. - Given 57.4 moles of Al₂(CO₃)₃, the total number of moles of oxygen atoms = 57.4 moles × 9. - The number of atoms is found using Avogadro's number (\(6.022 \times 10^{23}\) atoms/mole). This type of problem is common in chemistry for practicing mole and Avogadro's number calculations.
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