States of Matter
The substance that constitutes everything in the universe is known as matter. Matter comprises atoms which in turn are composed of electrons, protons, and neutrons. Different atoms combine together to give rise to molecules that act as a foundation for all kinds of substances. There are five states of matter based on their energies of attraction, namely solid, liquid, gases, plasma, and BEC (Bose-Einstein condensates).
Chemical Reactions and Equations
When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained using a chemical equation.
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I need help with 2 problems with my homework. I don't understand what I have to do or what equation to use.
![Use the following data to determine the moles of hydrogen gas produced with the
following reaction goes to completion. The molar mass of Mg is 24.305 g/mol. Give
your answer to five decimal places.
Mg (s) + 2 HCI (aq) → MgCl2 (aq) + H2 (g)
Mass of magnesium: 0.0267 g
Volume of 12 MHCI: 4.00 mL](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2d390e3f-8275-41b8-b687-67a83e0a6b78%2F6b6094eb-af8a-4b8d-8a80-20a2bb3a9105%2Fdhh96sd_processed.jpeg&w=3840&q=75)
![A student completes the experiment The Universal Gas Constant and obtains the
following data for one trial.
mass of magnesium (g):
0.0286
Initial gas volume (mL):
0.00
Final gas volume (mL):
32.85
Temperature ("C):
22.1
Atmospheric pressure (inHg): 29.23
Calculate the universal gas constant, R, for this trial. Assume that the water levels
inside and outside the eudiometer tube are the same; that is, assume Ah = 0.00 cm
water. Give your answer to two decimal places in the units of L-torr-mol-1.K?.
1 in Hg = 25.4 mmHg
1 cm water = 0.735559 mmHg
1 mol Mg = 24.305 g Mg](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2d390e3f-8275-41b8-b687-67a83e0a6b78%2F6b6094eb-af8a-4b8d-8a80-20a2bb3a9105%2F9ti29ip_processed.jpeg&w=3840&q=75)
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