Determine the mean or expected value of each random variable. 4. Find the mean of the probability distribution of the random variable X, which can take only the values of 1,2 and 3 5. the probabilities of a machine manufacturing 0, 1, 2, 3, 4 and 5 defective parts in one day are 0.75, 0.17, 0.04, 0.025, 0.01 and 0.005 respectively. find the mean of the probability distribution.

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Chapter1: Combinatorial Analysis
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Determine the mean or expected value of each random variable.

4. Find the mean of the probability distribution of the random variable X, which can take only the values of 1,2 and 3 

5. the probabilities of a machine manufacturing 0, 1, 2, 3, 4 and 5 defective parts in one day are 0.75, 0.17,  0.04, 0.025, 0.01 and 0.005 respectively. find the mean of the probability distribution. 

 

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ACTIVITY 1
A. Determine the mean or expected value of each Random Variable. Write your
answer in your answer sheets.
1.
4
12
20
P(s)
0.1
0.5
0.2
0.2
10
20
2.
P(t)
50%
12%
38%
1/2
1/12
1/2
1/6
1/3
1/5
W
3.
P(w)
1/10
1/5
4. Find the mean of the probability distribution of the random variable X, which
10
1
12
can take only the values 1, 2, and 3, given that P(1)
33
P(2) = =,
and P(3) =
33
5. The probabilities of a machine manufacturing 0, 1, 2, 3, 4, and 5 defective parts
in one day are 0.75, 0.17,0.04, 0.025, 0.01, and 0.005 respectively. Find the mean
of the probability distribution.
Transcribed Image Text:Home ACTIVITY 1 A. Determine the mean or expected value of each Random Variable. Write your answer in your answer sheets. 1. 4 12 20 P(s) 0.1 0.5 0.2 0.2 10 20 2. P(t) 50% 12% 38% 1/2 1/12 1/2 1/6 1/3 1/5 W 3. P(w) 1/10 1/5 4. Find the mean of the probability distribution of the random variable X, which 10 1 12 can take only the values 1, 2, and 3, given that P(1) 33 P(2) = =, and P(3) = 33 5. The probabilities of a machine manufacturing 0, 1, 2, 3, 4, and 5 defective parts in one day are 0.75, 0.17,0.04, 0.025, 0.01, and 0.005 respectively. Find the mean of the probability distribution.
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