The random variable $ x $ represents the number of cars per household in a town of 1000 households. Find the probability of randomly selecting a household that has between one and three cars, inclusive.| Cars | Households ||------|------------|| 0 | 135 || 1 | 418 || 2 | 242 || 3 | 122 || 4 | 83 |### Options- 0.782- 0.218- 0.418- 0.135### ExplanationThe table shows the distribution of the number of cars per household. To find the probability of a household having between one and three cars, inclusive, sum the number of households with 1, 2, and 3 cars, then divide by the total number of households (1000).\[\text{Number of households with 1 to 3 cars} = 418 + 242 + 122 = 782\]The probability is calculated as follows:\[P(1 \leq x \leq 3) = \frac{782}{1000} = 0.782\]

cars (x) 0 1 2 3 4 households P(X) 0.135 0.418 0.242 0.122 0.083

Answered: The random variable x represents the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The random variable x represents the number of cars per household in a town of 1000 households. Find the probability of randomly selecting a household that has between one and three cars, inclusive. Cars Households 135 418 2. 242 3. 122 4 83 O 0.782 O 0.218 O 0.418 O 0.135