**Determine the major product from the following reaction:**The reaction sequence involves:1) Treatment with LDA (Lithium Diisopropylamide)2) Addition of an aldehyde (structure is shown)3) Acidic workup with H3O^+**Explanation:**The provided image shows a chemical reaction starting with a cyclic ketone (cyclohexanone). The reaction sequence involves three steps:1. **LDA Treatment (Step 1):** - LDA (Lithium Diisopropylamide) is a strong, non-nucleophilic base that will deprotonate the α-hydrogen of the cyclohexanone to form an enolate anion.2. **Aldehyde Addition (Step 2):** - The enolate anion will react with the electrophilic carbonyl carbon of the aldehyde (shown in the image). This step forms a new carbon-carbon bond via nucleophilic addition, resulting in an alkoxide intermediate.3. **Acidic Workup (Step 3):** - The alkoxide intermediate is then protonated during the acidic workup with H3O^+ to form a β-hydroxy ketone as the final product.The overall reaction is an aldol addition reaction leading to the formation of a β-hydroxy ketone.

The major product of the reaction is given bellow. Reagent used : LDA, an aldehyde and H3O+

Answered: Determine the major product from the…

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Determine the major product from the following reaction: 1) LDA 2) O 3) H30*

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Determine the major product from the following reaction:**

The reaction sequence involves:

1) Treatment with LDA (Lithium Diisopropylamide)
2) Addition of an aldehyde (structure is shown)
3) Acidic workup with H3O^+

**Explanation:**

The provided image shows a chemical reaction starting with a cyclic ketone (cyclohexanone). The reaction sequence involves three steps:

1. **LDA Treatment (Step 1):**
- LDA (Lithium Diisopropylamide) is a strong, non-nucleophilic base that will deprotonate the α-hydrogen of the cyclohexanone to form an enolate anion.

2. **Aldehyde Addition (Step 2):**
- The enolate anion will react with the electrophilic carbonyl carbon of the aldehyde (shown in the image). This step forms a new carbon-carbon bond via nucleophilic addition, resulting in an alkoxide intermediate.

3. **Acidic Workup (Step 3):**
- The alkoxide intermediate is then protonated during the acidic workup with H3O^+ to form a β-hydroxy ketone as the final product.

The overall reaction is an aldol addition reaction leading to the formation of a β-hydroxy ketone.

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