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Determine the magnitudes of the reactions at A and B on the beam subjected to the point and distributed loads. w = wo- – kr32 3.5 kN/m 1.6 kN/m --- x B -6.8m- 2.5 -3.5 m- m 6.7 kN Answers: A = i kN B = i kN

Determine the magnitudes of the reactions at A and B on the beam subjected to the point and distributed loads. w = wo- – kr32 3.5 kN/m 1.6 kN/m --- x B -6.8m- 2.5 -3.5 m- m 6.7 kN Answers: A = i kN B = i kN

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Problem Statement:** Determine the magnitudes of the reactions at \(A\) and \(B\) on the beam subjected to the point and distributed loads. **Diagram Explanation:** - A horizontal beam is supported at points \(A\) and \(B\). - There is a distributed load over a portion of the beam starting with an intensity of \(3.5 \, \text{kN/m}\) at \(A\) and reducing linearly to \(1.6 \, \text{kN/m}\). - The distributed load follows the equation \(w = w_0 - kx^{3/2}\). - There is a point load of \(6.7 \, \text{kN}\) acting downward located \(6.8 \, \text{m}\) from \(A\). - The total distance from \(A\) to \(B\) is \(6.8 \, \text{m} + 2.5 \, \text{m} + 3.5 \, \text{m} = 12.8 \, \text{m}\). **Answers Section:** Calculate the reactions at: - \(A = \square \, \text{kN}\) - \(B = \square \, \text{kN}\)
Transcribed Image Text:**Problem Statement:** Determine the magnitudes of the reactions at \(A\) and \(B\) on the beam subjected to the point and distributed loads. **Diagram Explanation:** - A horizontal beam is supported at points \(A\) and \(B\). - There is a distributed load over a portion of the beam starting with an intensity of \(3.5 \, \text{kN/m}\) at \(A\) and reducing linearly to \(1.6 \, \text{kN/m}\). - The distributed load follows the equation \(w = w_0 - kx^{3/2}\). - There is a point load of \(6.7 \, \text{kN}\) acting downward located \(6.8 \, \text{m}\) from \(A\). - The total distance from \(A\) to \(B\) is \(6.8 \, \text{m} + 2.5 \, \text{m} + 3.5 \, \text{m} = 12.8 \, \text{m}\). **Answers Section:** Calculate the reactions at: - \(A = \square \, \text{kN}\) - \(B = \square \, \text{kN}\)
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