Determine the magnitude of the force that you need to apply to keep the block at rest

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Chapter1: Units, Trigonometry. And Vectors
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## Physics Mechanics: Force Analysis on an Inclined Plane

### Problem Statement:
A block of mass \(m = 10 \, \text{kg}\) sits on a frictionless ramp that has an inclination angle \(\theta = 20\) degrees. A rope connects the block to the ceiling. The rope hangs straight down and exerts a tension \(T = 50 \, \text{N}\) on the block. In order to keep the block stationary, you need to apply a force \( \vec{F} \) up along the ramp as shown in the diagram.

### Diagram Explanation:
The diagram depicts the physical setup of the problem:
- An inclined plane is shown with an angle of inclination \(\theta\).
- A block of mass \( m \) is placed on the inclined plane. The block is represented by a blue rectangular object labeled with \( m \).
- A rope connects the block to the ceiling, preventing it from moving down the incline. The tension in the rope is indicated as \( T \).
- A force \( \vec{F} \) is applied along the incline, directed upwards, which is represented by a pink arrow pointing up the ramp.

### Key Points:
- Inclination angle \( \theta = 20^\circ \)
- Block mass \( m = 10 \, \text{kg} \)
- Rope tension \( T = 50 \, \text{N} \)
- Applied force \( \vec{F} \) needs to be determined to keep the block stationary.

### Solution Strategy:
To solve for the applied force \( \vec{F} \):

1. **Resolve Forces Along the Incline:**
   - Gravitational force component parallel to the incline: \( mg \sin(\theta) \)
   - Tension force component along the incline: This needs to be adjusted according to the geometry
   - The applied force \( \vec{F} \) directly counteracts the combined effect of the gravitational component and tension along the incline.

2. **Newton's Second Law Along the Incline:**
   - Since the block is stationary, the net force along the incline must be zero.
   - Set up the equilibrium condition: \( \vec{F} = mg \sin(\theta) - T \cdot \cos(\theta) \)

3. **Calculate the Required Force:**
   - Substitute the given values into the equation to
Transcribed Image Text:## Physics Mechanics: Force Analysis on an Inclined Plane ### Problem Statement: A block of mass \(m = 10 \, \text{kg}\) sits on a frictionless ramp that has an inclination angle \(\theta = 20\) degrees. A rope connects the block to the ceiling. The rope hangs straight down and exerts a tension \(T = 50 \, \text{N}\) on the block. In order to keep the block stationary, you need to apply a force \( \vec{F} \) up along the ramp as shown in the diagram. ### Diagram Explanation: The diagram depicts the physical setup of the problem: - An inclined plane is shown with an angle of inclination \(\theta\). - A block of mass \( m \) is placed on the inclined plane. The block is represented by a blue rectangular object labeled with \( m \). - A rope connects the block to the ceiling, preventing it from moving down the incline. The tension in the rope is indicated as \( T \). - A force \( \vec{F} \) is applied along the incline, directed upwards, which is represented by a pink arrow pointing up the ramp. ### Key Points: - Inclination angle \( \theta = 20^\circ \) - Block mass \( m = 10 \, \text{kg} \) - Rope tension \( T = 50 \, \text{N} \) - Applied force \( \vec{F} \) needs to be determined to keep the block stationary. ### Solution Strategy: To solve for the applied force \( \vec{F} \): 1. **Resolve Forces Along the Incline:** - Gravitational force component parallel to the incline: \( mg \sin(\theta) \) - Tension force component along the incline: This needs to be adjusted according to the geometry - The applied force \( \vec{F} \) directly counteracts the combined effect of the gravitational component and tension along the incline. 2. **Newton's Second Law Along the Incline:** - Since the block is stationary, the net force along the incline must be zero. - Set up the equilibrium condition: \( \vec{F} = mg \sin(\theta) - T \cdot \cos(\theta) \) 3. **Calculate the Required Force:** - Substitute the given values into the equation to
### Physics Problem: Determining the Magnitude of Force \( F \)

**Objective:**
To determine the magnitude of the force \( F \) that needs to be applied to keep a block at rest.

The given problem requires you to apply concepts of equilibrium and force analysis. Use your knowledge of Newton's Laws and static equilibrium to solve for the force.

**Equation to Consider:**
\[
\sum F = 0
\]

**Steps for Solving the Problem:**

1. **Identify all forces acting on the block:**
   - Gravitational force (\( F_g \)) acting downward.
   - Normal force (\( N \)) acting perpendicular to the surface.
   - Applied force (\( F \)) which needs to be determined.
   - Frictional force (\( F_f \)) if any, acting opposite to the direction of potential movement.

2. **Set up the equilibrium equations:**
   - For vertical forces: \( \sum F_y = 0 \)
   - For horizontal forces: \( \sum F_x = 0 \)
   
3. **Solve the equations for the unknown force \( F \).**

**Example Analysis:**

- Assume there is no friction for simplicity.
- The block is resting, so the forces in the vertical direction must balance.
- If there are no other forces acting horizontally, \( F \) will need to balance any horizontal components.

Use these steps as a guideline to derive the precise value of the force \( F \) in your specific situation.

---

**Note:**
There are no graphs or diagrams provided in the given text. For visual learners, it would be beneficial to include a free-body diagram illustrating the block and the forces acting on it to aid in understanding. Draw a rectangle (representing the block) with vectors showing the forces \( F_g \) (downward), \( N \) (upward), and \( F \) in the required direction.
Transcribed Image Text:### Physics Problem: Determining the Magnitude of Force \( F \) **Objective:** To determine the magnitude of the force \( F \) that needs to be applied to keep a block at rest. The given problem requires you to apply concepts of equilibrium and force analysis. Use your knowledge of Newton's Laws and static equilibrium to solve for the force. **Equation to Consider:** \[ \sum F = 0 \] **Steps for Solving the Problem:** 1. **Identify all forces acting on the block:** - Gravitational force (\( F_g \)) acting downward. - Normal force (\( N \)) acting perpendicular to the surface. - Applied force (\( F \)) which needs to be determined. - Frictional force (\( F_f \)) if any, acting opposite to the direction of potential movement. 2. **Set up the equilibrium equations:** - For vertical forces: \( \sum F_y = 0 \) - For horizontal forces: \( \sum F_x = 0 \) 3. **Solve the equations for the unknown force \( F \).** **Example Analysis:** - Assume there is no friction for simplicity. - The block is resting, so the forces in the vertical direction must balance. - If there are no other forces acting horizontally, \( F \) will need to balance any horizontal components. Use these steps as a guideline to derive the precise value of the force \( F \) in your specific situation. --- **Note:** There are no graphs or diagrams provided in the given text. For visual learners, it would be beneficial to include a free-body diagram illustrating the block and the forces acting on it to aid in understanding. Draw a rectangle (representing the block) with vectors showing the forces \( F_g \) (downward), \( N \) (upward), and \( F \) in the required direction.
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