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determine the limiting reaction in the following sn2 reaction given 2.00mmol of sodium saccharin and 0.16mL of iodoethane. yielding product of 0.151g N-ethylsaccharin

determine the limiting reaction in the following sn2 reaction given 2.00mmol of sodium saccharin and 0.16mL of iodoethane. yielding product of 0.151g N-ethylsaccharin

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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determine the limiting reaction in the following sn2 reaction given 2.00mmol of sodium saccharin and 0.16mL of iodoethane. yielding product of 0.151g N-ethylsaccharin

The diagram shows a chemical reaction involving a sodium salt of saccharin reacting with ethyl iodide (CH₃CH₂I). **Reactants:** - A sodium salt of saccharin depicted as a benzene ring fused with a nitrogen and sulfur heterocycle. The nitrogen carries a negative charge, neutralized by the sodium ion (Na⁺). - Ethyl iodide (CH₃CH₂I) shown on the right side of the equation. **Products:** - The reaction yields two possible isomers: 1. One where the ethyl group (CH₂CH₃) is attached to the nitrogen atom. 2. Another where the ethyl group is attached to the oxygen atom within the same heterocycle. - Both products are shown within a bracket, indicating they are possible outcomes of the reaction. - Sodium iodide (NaI) is also produced as a by-product. **Diagram Explanation:** - Arrows indicate the transformation from reactants to products. - The word "OR" between the isomer structures suggests alternative product formation depending on reaction conditions.
Transcribed Image Text:The diagram shows a chemical reaction involving a sodium salt of saccharin reacting with ethyl iodide (CH₃CH₂I). **Reactants:** - A sodium salt of saccharin depicted as a benzene ring fused with a nitrogen and sulfur heterocycle. The nitrogen carries a negative charge, neutralized by the sodium ion (Na⁺). - Ethyl iodide (CH₃CH₂I) shown on the right side of the equation. **Products:** - The reaction yields two possible isomers: 1. One where the ethyl group (CH₂CH₃) is attached to the nitrogen atom. 2. Another where the ethyl group is attached to the oxygen atom within the same heterocycle. - Both products are shown within a bracket, indicating they are possible outcomes of the reaction. - Sodium iodide (NaI) is also produced as a by-product. **Diagram Explanation:** - Arrows indicate the transformation from reactants to products. - The word "OR" between the isomer structures suggests alternative product formation depending on reaction conditions.
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