Determine the hybridization of the central atom for each molecule. -13: :ci: :CI: sp sp² sp³ sp³ d sp³ d² -CI: SIC sp sp² sp³ sp³ d sp³ d²

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Chapter13: Structure And Shape
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## Hybridization of Central Atoms in Given Molecules

**Task:** Determine the hybridization of the central atom for each molecule.

### Molecule 1
**Description:** This molecule consists of an aluminum (Al) atom at the center bonded to four chlorine (Cl) atoms in a tetrahedral arrangement. Each chlorine atom has three lone pairs of electrons.

### Molecule 2
**Description:** This molecule features a central carbon (C) atom double-bonded to two sulfur (S) atoms in a linear structure. Each sulfur atom has two lone pairs of electrons.

### Hybridization Options
For both molecules, select the appropriate hybridization for the central atom from the following options:
- **sp**
- **sp²**
- **sp³**
- **sp³d**
- **sp³d²**

**Diagrams Explanation:**

1. **Molecule 1 (AlCl₄⁻):**
   - The central aluminum (Al) atom in the tetrahedral structure.
   - Four single bonds with chlorine (Cl).
   - Each chlorine atom has six valence electrons represented by three lone pairs.

2. **Molecule 2 (CS₂):**
   - The central carbon (C) atom is double-bonded to two sulfur (S) atoms.
   - Linear arrangement of atoms.
   - Each sulfur atom has four valence electrons represented by two lone pairs.

**Task Tip:** Focus on the number of electron groups around the central atom to determine its hybridization:
- **sp**: 2 groups
- **sp²**: 3 groups
- **sp³**: 4 groups
- **sp³d**: 5 groups
- **sp³d²**: 6 groups
Transcribed Image Text:## Hybridization of Central Atoms in Given Molecules **Task:** Determine the hybridization of the central atom for each molecule. ### Molecule 1 **Description:** This molecule consists of an aluminum (Al) atom at the center bonded to four chlorine (Cl) atoms in a tetrahedral arrangement. Each chlorine atom has three lone pairs of electrons. ### Molecule 2 **Description:** This molecule features a central carbon (C) atom double-bonded to two sulfur (S) atoms in a linear structure. Each sulfur atom has two lone pairs of electrons. ### Hybridization Options For both molecules, select the appropriate hybridization for the central atom from the following options: - **sp** - **sp²** - **sp³** - **sp³d** - **sp³d²** **Diagrams Explanation:** 1. **Molecule 1 (AlCl₄⁻):** - The central aluminum (Al) atom in the tetrahedral structure. - Four single bonds with chlorine (Cl). - Each chlorine atom has six valence electrons represented by three lone pairs. 2. **Molecule 2 (CS₂):** - The central carbon (C) atom is double-bonded to two sulfur (S) atoms. - Linear arrangement of atoms. - Each sulfur atom has four valence electrons represented by two lone pairs. **Task Tip:** Focus on the number of electron groups around the central atom to determine its hybridization: - **sp**: 2 groups - **sp²**: 3 groups - **sp³**: 4 groups - **sp³d**: 5 groups - **sp³d²**: 6 groups
### Molecular Geometry and Hybridization

The image depicts a molecule with phosphorous (P) bonded to three fluorine (F) atoms. The arrangement of the atoms suggests it is a T-shaped molecule, which indicates three bonding pairs and two lone pairs of electrons around the central phosphorus atom.

To predict the hybridization of the central atom, we use the concept of electron domain geometry. The phosphorus atom has five electron domains (three bonding pairs and two lone pairs).

#### Hybridization Options:
- **sp** 
- **sp²** 
- **sp³**
- **sp³d**
- **sp³d²**

From the provided options and the molecular geometry, the correct hybridization for phosphorus in this molecule should be determined by counting the total number of electron groups around it. In this case, the phosphorus atom has a total of five electron pairs, so the hybridization is **sp³d**.

Select the correct hybridization state based on the information provided.

- ( ) sp
- ( ) sp²
- ( ) sp³
- (○) sp³d
- ( ) sp³d²
Transcribed Image Text:### Molecular Geometry and Hybridization The image depicts a molecule with phosphorous (P) bonded to three fluorine (F) atoms. The arrangement of the atoms suggests it is a T-shaped molecule, which indicates three bonding pairs and two lone pairs of electrons around the central phosphorus atom. To predict the hybridization of the central atom, we use the concept of electron domain geometry. The phosphorus atom has five electron domains (three bonding pairs and two lone pairs). #### Hybridization Options: - **sp** - **sp²** - **sp³** - **sp³d** - **sp³d²** From the provided options and the molecular geometry, the correct hybridization for phosphorus in this molecule should be determined by counting the total number of electron groups around it. In this case, the phosphorus atom has a total of five electron pairs, so the hybridization is **sp³d**. Select the correct hybridization state based on the information provided. - ( ) sp - ( ) sp² - ( ) sp³ - (○) sp³d - ( ) sp³d²
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