Determine the horsepower developed by a passenger car traveling at a speed of 65 mi/h on an upgrade of 9 percent with a smooth pavement. The weight of the car is 3,000 lb and the cross-sectional area of the car is 35 ft². (Assume the density of air is 0.0766 lb/ft³, and the aerodynamic drag coefficient is 0.4. Use the following equation for the rolling resistance R in lb: R = (Crs + 2.15Cu²)W for which Crs = 0.012, CÃ = 0.650 × 10−6 sec²/ft², u is the vehicle speed in mi/h, and W is the weight of the vehicle in lb.) hp Need Help? Read It Watch It
Determine the horsepower developed by a passenger car traveling at a speed of 65 mi/h on an upgrade of 9 percent with a smooth pavement. The weight of the car is 3,000 lb and the cross-sectional area of the car is 35 ft². (Assume the density of air is 0.0766 lb/ft³, and the aerodynamic drag coefficient is 0.4. Use the following equation for the rolling resistance R in lb: R = (Crs + 2.15Cu²)W for which Crs = 0.012, CÃ = 0.650 × 10−6 sec²/ft², u is the vehicle speed in mi/h, and W is the weight of the vehicle in lb.) hp Need Help? Read It Watch It
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Determine the horsepower developed by a passenger car traveling at a speed of 65 mi/h on an upgrade of 9 percent with a smooth pavement. The weight of the car is 3,000 lb and the cross-sectional area of the car is 35 ft2. (Assume the density of air is 0.0766 lb/ft3, and the aerodynamic drag coefficient is 0.4. Use the following equation for the rolling resistance Rr in lb:
Rr = (Crs + 2.15Crvu2)W
for which Crs = 0.012, Crv = 0.650 ✕ 10−6 sec2/ft2, u is the vehicle speed in mi/h, and W is the weight of the vehicle in lb.)
hp

Transcribed Image Text:Determine the horsepower developed by a passenger car traveling at a speed of 65 mi/h on an upgrade of 9 percent with a
smooth pavement. The weight of the car is 3,000 lb and the cross-sectional area of the car is 35 ft². (Assume the density
of air is 0.0766 lb/ft³, and the aerodynamic drag coefficient is 0.4. Use the following equation for the rolling resistance R in
lb:
R = (Crs + 2.15Cu²)W
for which Crs
= 0.012, CÃ = 0.650 × 10−6 sec²/ft², u is the vehicle speed in mi/h, and W is the weight of the vehicle in lb.)
hp
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