determine the forces in each member.
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- A car is stuck in the mud. A tow truck pulls on the car with the arrangement shown in the figure below. The tow cable is under a tension of of 2,060 N and pulls downward and to the left on the pin at its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut; that is, each is a bar whose weight is small compared to the forces it exerts and which exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as follows. Make a guess as to which way (pushing or pulling) each force acts on the top pin. Draw a free-body diagram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equations. From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. reversed, but the absolute value…It says this one is wrongPlease help with the attached problem.
- Provide a screenshot of a scenario where the net force is 50n to the left and there is at least 1 member on each side.The uniform rod in the figure shown weighs 420 kN and has its center of gravity at G. a) Compute the reaction at the smooth surface A. b) Determine the reaction at the smooth surface B. c) Calculate the tension in the cable. 420KN G Cable 4m 2 mJust need D A) 68.46 rad/s^2 B) 1.36 rad/s^2 C)59.95 N