29a) Label the forces acting on the beam (6). There will be a horizontal and vertical force exerted by the hinge. b) Write down the (x,y) components of T. c) Write down the equations for EF(x,y). Note: All the weights in are given in N, not mass in kg. d) With the pivot point at the hinge, determine the equation for the Et. Start with Et = ±TN ±Tv ±Twbear ±Twbeam ±TT ±Twgoodies = 0 %3D Remember, there are several steps to get this equation. There should be only 1 variable (T) in this equation. e) Solve the tequation for the tension, T. f) Evaluate the (x,y) components of T, then from x equation, find the horizontal (normal) force from the hinge. g) From the y equation, find the vertical force from the hinge. or the maximum distance the bear can walk: The torque equation from part d will be the same, except: r for the bear will be x (not 1), and tension T = 900, (not a variable). h) Re-write the torque eq. with the new adjustments. i) Solve the new torque equation for x, the distance the bear can walk before the cable breaks. You can check (some of) your answers with the back of the book.

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29a) Label the forces acting on the beam (6).
There will be a horizontal and vertical force exerted by the hinge.
b) Write down the (x,y) components of T.
C) Write down the equations for EF(x,y). Note: All the weights in
are given in N, not mass in kg.
d) With the pivot point at the hinge, determine the equation for
the Et. Start with Et = ±tn ±Tv ±Twbear ±Twbeam ±T ±twgoodies =
Remember, there are several steps to get this equation. There
should be only 1 variable (T) in this equation.
e) Solve the tequation for the tension, T.
f) Evaluate the (x,y) components of T, then from x equation, find
the horizontal (normal) force from the hinge.
g) From the y equation, find the vertical force from the hinge.
or the maximum distance the bear can walk:
The torque equation from part d will be the same, except:
r for the bear will be x (not 1), and tension T = 900, (not a
variable).
h) Re-write the torque eq. with the new adjustments.
i) Solve the new torque equation for x, the distance the bear can
walk before the cable breaks.
You can check (some of) your answers with the back of the book.
Transcribed Image Text:29a) Label the forces acting on the beam (6). There will be a horizontal and vertical force exerted by the hinge. b) Write down the (x,y) components of T. C) Write down the equations for EF(x,y). Note: All the weights in are given in N, not mass in kg. d) With the pivot point at the hinge, determine the equation for the Et. Start with Et = ±tn ±Tv ±Twbear ±Twbeam ±T ±twgoodies = Remember, there are several steps to get this equation. There should be only 1 variable (T) in this equation. e) Solve the tequation for the tension, T. f) Evaluate the (x,y) components of T, then from x equation, find the horizontal (normal) force from the hinge. g) From the y equation, find the vertical force from the hinge. or the maximum distance the bear can walk: The torque equation from part d will be the same, except: r for the bear will be x (not 1), and tension T = 900, (not a variable). h) Re-write the torque eq. with the new adjustments. i) Solve the new torque equation for x, the distance the bear can walk before the cable breaks. You can check (some of) your answers with the back of the book.
knowns:
Bear Mass = 700N
Beam Mass= 200N
Food
Beam L=
%3D
8ON
BEAR
40°
Hinge
BEAM
Feod
tom
Transcribed Image Text:knowns: Bear Mass = 700N Beam Mass= 200N Food Beam L= %3D 8ON BEAR 40° Hinge BEAM Feod tom
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