[ series of concentrated axle loads ] Determine the following:a. Maximum negative shear at Bb. Maximum positive shear at Bc. Maximum positive moment at Bd. Maximum reaction at C Use stored values while solving4 decimal places in final answer -5 mB- 10 m -숲a}44.5 kN 22.25 kN66.75 kN35.6 kN¢0¢ ©12 32m1.5 m2.5 m 5 m3 m1.5 mIm2m44.5 kN35.6 kN66.75 kNd d d dB+44.5 kN35.6 kN 66.75 kNb b bB44.5 kN2m1.5 m66.75 KN1.5 m44.5 kN35.6 kN66.75 kNb b b bB2m2.5 m1.5 mB1.5 m22.25 kN22.25 kN2.5 m1522.25 kN2.5 m22.25 kN12.5 mB0.66710 m-0.3336 m7.5 m4m15(c) Loading Position 1(d) Loading Position 2(e) Loading Position 3(f) Loading Position 4

Answered: Image /qna-images/answer/c966a426-1665-4560-937c-b9a7617d4d39.jpg

Answered: Determine the following: a. Maximum…

Determine the following: a. Maximum negative shear at B b. Maximum positive shear at B c. Maximum positive moment at B d. Maximum reaction at C

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

[ series of concentrated axle loads ]

Determine the following:

a. Maximum negative shear at B

b. Maximum positive shear at B

c. Maximum positive moment at B

d. Maximum reaction at C

Use stored values while solving

4 decimal places in final answer

-5 m
B
- 10 m -
숲
a}
44.5 kN 22.25 kN
66.75 kN
35.6 kN
¢0¢ ©
1
2 3
2m
1.5 m
2.5 m

5 m
3 m
1.5 m
Im
2m
44.5 kN
35.6 kN
66.75 kN
d d d d
B
+
44.5 kN
35.6 kN 66.75 kN
b b b
B
44.5 kN
2m
1.5 m
66.75 KN
1.5 m
44.5 kN
35.6 kN
66.75 kN
b b b b
B
2m
2.5 m
1.5 m
B
1.5 m
22.25 kN
22.25 kN
2.5 m
15
22.25 kN
2.5 m
22.25 kN
1
2.5 m
B
0.667
10 m
-0.333
6 m
7.5 m
4m
15
(c) Loading Position 1
(d) Loading Position 2
(e) Loading Position 3
(f) Loading Position 4

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Step 2: Determine position of loads for negative shear at B

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Step 3: Determine maximum negative shear at B

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Step 4: Determine position of loads for positive shear at B

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Step 5: Determine maximum positive shear at B

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Step 6: Determine position of maximum moment at B

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Step 7: Determine maximum moment at B

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Step 8: Determine maximum support reaction at C

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