Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Leta = 4 m, b = 3m, PB = 60 kN, Pc = 85 kN, and PE = 25 KN. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. a Answer: Ay= a PB i B PB RO a B Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Pc a C qo Pc D b D a Dy PE a PE E kN, Dy= i E x kN.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a = 4 m, b = 3 m, PB
= 60 kN, Pc = 85 kN, and PE = 25 kN. Construct the shear-force and bending-moment diagrams on paper and use the results to
answer the questions in the subsequent parts of this GO exercise.
A
Ay
Answer: Ay
a
=
a
PB
Mo
B
PB
a
Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the
red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)
B
Pc
a
b
Pc
D
b
D
a
Dy
a
PE
kN, Dy=
E
PE
X
E
X
kN.
Transcribed Image Text:Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a = 4 m, b = 3 m, PB = 60 kN, Pc = 85 kN, and PE = 25 kN. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. A Ay Answer: Ay a = a PB Mo B PB a Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) B Pc a b Pc D b D a Dy a PE kN, Dy= E PE X E X kN.
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