Determine the final temperature of a 377 g sample of iron when 2.64 kJ of heat is added. The initial temperature of the sample was 18.8 oC. The specific heat capacity of iron is 0.449 J/g-K.

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### Determining the Final Temperature of a Heated Iron Sample

In this example, we aim to calculate the final temperature of a 377 g sample of iron when 2.64 kJ of heat is added. The initial temperature of the sample was 18.8°C. The specific heat capacity of iron is given as 0.449 J/g·K.

#### Problem Statement:
"Determine the final temperature of a 377 g sample of iron when 2.64 kJ of heat is added. The initial temperature of the sample was 18.8°C. The specific heat capacity of iron is 0.449 J/g·K."

#### Given Data:
- Mass of iron sample (m): 377 g
- Heat added (q): 2.64 kJ (2640 J)
- Initial temperature (T₁): 18.8°C
- Specific heat capacity of iron (c): 0.449 J/g·K

#### Solution:
To determine the final temperature (T₂), we can use the formula for heat transfer:
\[ q = m \cdot c \cdot \Delta T \]

Where:
- \( q \) is the heat added,
- \( m \) is the mass of the sample,
- \( c \) is the specific heat capacity,
- \( \Delta T \) is the change in temperature (T₂ - T₁).

Rearranging to solve for \( \Delta T \):
\[ \Delta T = \frac{q}{m \cdot c} \]

Substitute the given values into the equation:
\[ \Delta T = \frac{2640 \text{ J}}{377 \text{ g} \cdot 0.449 \text{ J/g·K}} \]
\[ \Delta T \approx 15.4 \text{ K} \]

Now, calculate the final temperature:
\[ T₂ = T₁ + \Delta T \]
\[ T₂ = 18.8°C + 15.4 \text{ K} \]
\[ T₂ \approx 34.2°C \]

Therefore, the final temperature of the iron sample after adding 2.64 kJ of heat is approximately 34.2°C.

**Note:** In the context of this calculation, an increase in temperature (ΔT) in degrees Celsius is equivalent to an increase in temperature in Kelvin since the size of a degree
Transcribed Image Text:### Determining the Final Temperature of a Heated Iron Sample In this example, we aim to calculate the final temperature of a 377 g sample of iron when 2.64 kJ of heat is added. The initial temperature of the sample was 18.8°C. The specific heat capacity of iron is given as 0.449 J/g·K. #### Problem Statement: "Determine the final temperature of a 377 g sample of iron when 2.64 kJ of heat is added. The initial temperature of the sample was 18.8°C. The specific heat capacity of iron is 0.449 J/g·K." #### Given Data: - Mass of iron sample (m): 377 g - Heat added (q): 2.64 kJ (2640 J) - Initial temperature (T₁): 18.8°C - Specific heat capacity of iron (c): 0.449 J/g·K #### Solution: To determine the final temperature (T₂), we can use the formula for heat transfer: \[ q = m \cdot c \cdot \Delta T \] Where: - \( q \) is the heat added, - \( m \) is the mass of the sample, - \( c \) is the specific heat capacity, - \( \Delta T \) is the change in temperature (T₂ - T₁). Rearranging to solve for \( \Delta T \): \[ \Delta T = \frac{q}{m \cdot c} \] Substitute the given values into the equation: \[ \Delta T = \frac{2640 \text{ J}}{377 \text{ g} \cdot 0.449 \text{ J/g·K}} \] \[ \Delta T \approx 15.4 \text{ K} \] Now, calculate the final temperature: \[ T₂ = T₁ + \Delta T \] \[ T₂ = 18.8°C + 15.4 \text{ K} \] \[ T₂ \approx 34.2°C \] Therefore, the final temperature of the iron sample after adding 2.64 kJ of heat is approximately 34.2°C. **Note:** In the context of this calculation, an increase in temperature (ΔT) in degrees Celsius is equivalent to an increase in temperature in Kelvin since the size of a degree
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