Determine the equilibrium constant, Kgoal, for the reaction 4PC15 (g) P4(s) +10C12 (g), Kgoal = ? by making use of the following information: 1. P4(s) +6C12 (g) = 4PC13 (g), 2. PCls (g) PC13 (g) + Cl₂ (g), = K₁2.00 × 10¹⁹ K2 1.13 x 10-²

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Part B
Determine the equilibrium constant, Kgoal, for the reaction
by making use of the following information:
1. P4(s) +6C12 (g) = 4PCl3 (g),
2. PCl; (g) → PCl3 (g) + Cl₂ (g),
Express your answer numerically.
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Kgoal=
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VE ΑΣΦ
4PC15 (g) = P4(s) +10Cl2 (g), Kgoal = ?
MacBook Air
F
P Pearson
Kgoal = (K₁ × K₂ × K3) ¹/2
F8
K₁ = 2.00 × 10¹⁹
K₂ = 1.13 x 10-²
O
INNIN.
HANNES
?
F10
Transcribed Image Text:Part B Determine the equilibrium constant, Kgoal, for the reaction by making use of the following information: 1. P4(s) +6C12 (g) = 4PCl3 (g), 2. PCl; (g) → PCl3 (g) + Cl₂ (g), Express your answer numerically. ► View Available Hint(s) Kgoal= Submit Provide Feedback VE ΑΣΦ 4PC15 (g) = P4(s) +10Cl2 (g), Kgoal = ? MacBook Air F P Pearson Kgoal = (K₁ × K₂ × K3) ¹/2 F8 K₁ = 2.00 × 10¹⁹ K₂ = 1.13 x 10-² O INNIN. HANNES ? F10
Expert Solution
Step 1

Answer:

In this question we have to establish the relation between Kgoal, K1 and K2 for the given reactions.

Given data:

K1=2.00×1019K2=1.13×10-2

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