Determine the equilibrium constant, Keq, for the following reaction at T = 750.0 K: CO + OH →→→→→→→ CO₂ + H The rate coefficient in the forward direction is given by 1.50 2.08 kJ/mol) kf(T)=5.4 x 10-14_cm³ 3 T exp molec-s298K RT and the rate coefficient in the reverse direction is given by k (T)=2.51 x 10-10, cm ³ -111.0 kJ/mol) molec.s RT exp

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Determine the equilibrium constant, Keq, for the following reaction at
T = 750.0 K:
CO + OH →→→→→→→→ CO₂ + H
The rate coefficient in the forward direction is given by
1.50
2.08 kJ/mol
kf(T) = 5.4 x 10-14_cm³
molec-s298K
RT
and the rate coefficient in the reverse direction is given by
cm³
3
-111.0 kJ/mol)
k, (T)=2.51 x 10-10
molec.s
RT
3
T
exp
exp
Transcribed Image Text:Determine the equilibrium constant, Keq, for the following reaction at T = 750.0 K: CO + OH →→→→→→→→ CO₂ + H The rate coefficient in the forward direction is given by 1.50 2.08 kJ/mol kf(T) = 5.4 x 10-14_cm³ molec-s298K RT and the rate coefficient in the reverse direction is given by cm³ 3 -111.0 kJ/mol) k, (T)=2.51 x 10-10 molec.s RT 3 T exp exp
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